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CAT 2017 · Slot 1

A full-length paper in the 2017 pattern. Sit it under exam conditions with solutions locked until you submit, or open it in learn mode and check each answer as you go.

100questions
180 min60 min per section
29TITA, no negative marks
23/58/19easy / medium / hard

Section-wise pattern and topics

Sections run in this order with their own timer, as in CAT 2017.

Verbal Ability & Reading Comprehension · 34 questions · 60 min

  • Reading Comprehension27
  • Para Jumble4
  • Odd Sentence Out3

Data Interpretation & Logical Reasoning · 32 questions · 60 min

  • Grid4
  • Tables4
  • Games & Tournaments4
  • Venn Diagrams4
  • Linear Arrangement4
  • Stock Prices4
  • Selection & Team Formation4
  • Scores & Rankings4

Quantitative Ability · 34 questions · 60 min

  • Progressions3
  • Percentages2
  • Profit, Loss & Discount2
  • Coordinate Geometry2
  • Simple & Compound Interest1
  • Ratio & Proportion1
  • Mixtures & Alligation1
  • Averages1
  • Escalators1
  • Circular Motion1
  • Time & Work1
  • Pipes & Cisterns1
  • Ratio & Partnership1
  • Races1
  • Quadratic Equations1
  • Inequalities & Modulus1
  • Logarithms1
  • Linear Equations1
  • Maxima & Minima1
  • Polynomials1
  • Triangles1
  • Triangles & Circles1
  • Mensuration1
  • Polygons1
  • Similar Triangles1
  • Divisors1
  • Remainders1
  • Permutations & Combinations1
  • Probability1

Sample question from this paper

Simple & Compound Interest · medium

A sum invested at 20% per annum, compounded annually, earns Rs 512 more interest over 3 years than the same sum would earn at simple interest. Find the sum.
  1. A. Rs 3,750
  2. B. Rs 4,000
  3. C. Rs 4,200
  4. D. Rs 4,500
Show answer and solution
Answer: B
Let the sum be P.

CI for 3 years = P(1.2³ − 1) = P(1.728 − 1) = 0.728P.
SI for 3 years = P × 0.20 × 3 = 0.6P.

Difference = 0.728P − 0.6P = 0.128P = 512, so P = 512/0.128 = Rs 4,000.

Check: SI = 4000×0.6 = 2,400; CI = 4000×0.728 = 2,912; difference = 512. ✓