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CAT 2020 · Slot 3

A full-length paper in the 2020 pattern. Sit it under exam conditions with solutions locked until you submit, or open it in learn mode and check each answer as you go.

76questions
120 min40 min per section
24TITA, no negative marks
21/41/14easy / medium / hard

Section-wise pattern and topics

Sections run in this order with their own timer, as in CAT 2020.

Verbal Ability & Reading Comprehension · 26 questions · 40 min

  • Reading Comprehension18
  • Para Jumble3
  • Para Summary2
  • Odd Sentence Out2
  • Sentence Placement1

Data Interpretation & Logical Reasoning · 24 questions · 40 min

  • Startup funding5
  • Grid arrangement5
  • Elimination rounds5
  • Linear arrangement5
  • Compound Interest3
  • Simple vs Compound Interest1

Quantitative Ability · 26 questions · 40 min

  • Percentages2
  • Mixtures & Alligations2
  • Time, Speed & Distance2
  • Profit & Loss1
  • Simple & Compound Interest1
  • Averages1
  • Time & Work1
  • Ratio & Partnership1
  • Quadratic Equations1
  • Modulus1
  • Functions1
  • Logarithms1
  • Progressions1
  • Equations1
  • Sequences1
  • Coordinate Geometry1
  • Triangles1
  • Mensuration1
  • Polygons1
  • Remainders1
  • Permutations & Combinations1
  • Probability1
  • Maxima & Minima1

Sample question from this paper

Time, Speed & Distance · medium

Two trains of lengths 180 m and 120 m cross each other completely in 10 seconds when running in opposite directions, and in 50 seconds when running in the same direction. What is the speed of the faster train?
  1. A. 43.2 km/h
  2. B. 54 km/h
  3. C. 64.8 km/h
  4. D. 72 km/h
Show answer and solution
Answer: C
Distance to be covered in either case = 180 + 120 = 300 m.

Opposite directions: a + b = 300/10 = 30 m/s.
Same direction: a − b = 300/50 = 6 m/s.

So a = 18 m/s and b = 12 m/s. Faster train = 18 × 18/5 = 64.8 km/h.

43.2 km/h is the slower train (12 m/s) — a common trap.