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Class 9 Maths Chapter 2: Introduction to Linear Polynomials — Notes, Examples & Practice

Many everyday quantities change by the same amount each step: a taxi fare per kilometre, a plant that grows 2 cm a week, a phone balance that drops ₹10 a day. This chapter gives you the algebra for such situations — linear polynomials of the form ax+bax + b — and shows how to spot them in tables and patterns, use them to predict, and draw them as straight lines.

1Polynomials: terms, coefficients and degree

A polynomial in xx is a sum of terms of the form (number) × xnx^{n}, where every power nn is a whole number (0, 1, 2, 3, …). For example, 4x3−2x+74x^3 - 2x + 7 is a polynomial with three terms.

In each term the number in front is the coefficient; a term with no xx (like 7) is the constant term. The highest power of xx that appears with a non-zero coefficient is the degree.

Expressions such as 1x\dfrac{1}{x}, x\sqrt{x} or x−2x^{-2} are not polynomials because the power of xx is not a whole number. By degree, polynomials are named constant (0), linear (1), quadratic (2) and cubic (3).

Key formulas & definitions
  • Polynomial: anxn+⋯+a1x+a0a_n x^n + \dots + a_1 x + a_0, powers are whole numbers.
  • Degree = highest power with a non-zero coefficient.
  • Linear (degree 1): ax+bax + b with a≠0a \neq 0. Quadratic: degree 2. Cubic: degree 3.
Worked example 1

Which of these are polynomials? For each polynomial, give its degree: (i) 5−3x2+x5 - 3x^2 + x (ii) x+2xx + \dfrac{2}{x} (iii) 3 x−1\sqrt{3}\,x - 1 (iv) 77.

  1. (i) Powers 0, 2, 1 are whole numbers → polynomial, degree 2.
  2. (ii) 2x=2x−1\dfrac{2}{x} = 2x^{-1} has power −1-1 → not a polynomial.
  3. (iii) The coefficient 3\sqrt{3} may be irrational; the power of xx is 1 → polynomial, degree 1.
  4. (iv) 7=7x07 = 7x^0 → constant polynomial, degree 0.

Answer: (i), (iii), (iv) are polynomials with degrees 2, 1, 0.

Common mistakes
  • Thinking 3x\sqrt{3}x is not a polynomial — only the power of xx must be a whole number; coefficients can be any real numbers.
  • Reading the degree from the first term written instead of the highest power.

2Linear polynomials and their zeros

A linear polynomial p(x)=ax+bp(x) = ax + b (a≠0a \neq 0) changes by exactly aa every time xx increases by 1. To evaluate it, substitute a number: if p(x)=3x−6p(x) = 3x - 6, then p(4)=3(4)−6=6p(4) = 3(4) - 6 = 6.

A zero of a polynomial is a value of xx that makes it equal to 0. For ax+bax + b, solve ax+b=0ax + b = 0 to get x=−bax = -\dfrac{b}{a}. Every linear polynomial has exactly one zero.

On a graph of y=ax+by = ax + b, the zero is where the line crosses the x-axis, because there y=0y = 0.

Key formulas & definitions
  • Zero of ax+bax + b: x=−bax = -\dfrac{b}{a}
  • p(k)p(k) means: replace every xx by kk.
  • Graphically, the zero is the x-intercept of y=ax+by = ax + b.
Worked example 1

Find the zero of p(x)=5x+20p(x) = 5x + 20 and check it.

  1. 5x+20=0⇒5x=−20⇒x=−45x + 20 = 0 \Rightarrow 5x = -20 \Rightarrow x = -4.
  2. Check: p(−4)=5(−4)+20=0p(-4) = 5(-4) + 20 = 0 ✓.

Answer: x=−4x = -4.

Worked example 2

A gym charges a ₹500 joining fee plus ₹300 per month. Write the total cost after mm months as a polynomial and find the cost for a year.

  1. Each month adds ₹300 and the fee is paid once: C(m)=300m+500C(m) = 300m + 500.
  2. C(12)=300×12+500=3600+500=4100C(12) = 300 \times 12 + 500 = 3600 + 500 = 4100.

Answer: C(m)=300m+500C(m) = 300m + 500; ₹4,100 for a year.

Trick / memory aid

Zero of ax+bax + b: “move bb across, divide by aa” — the sign of bb flips.

Common mistakes
  • Writing the zero of 2x−82x - 8 as −4-4. Solve: 2x=82x = 8, so x=4x = 4.
  • Confusing p(0)p(0) (the constant term, i.e. the y-intercept) with the zero of pp.

3Linear patterns

A pattern is linear when the difference between consecutive terms is constant. Look at matchstick squares in a row: 4, 7, 10, 13, … sticks. Each new square adds 3 sticks.

To write the rule, the constant difference becomes the coefficient of nn. Then fix the constant by matching the first term: 3n+b3n + b must equal 4 when n=1n = 1, so b=1b = 1. Rule: 3n+13n + 1.

Making a table of nn and the value, and writing the differences underneath, is the fastest way to decide whether a pattern is linear.

Key formulas & definitions
  • Linear pattern ⇔ constant first difference dd.
  • Rule: value =d⋅n+(first term−d)= d \cdot n + (\text{first term} - d).
Worked example 1

Tables in a canteen are joined in a line. 1 table seats 6, 2 tables seat 10, 3 tables seat 14. How many people can sit at 25 tables?

  1. Differences: 10−6=410 - 6 = 4, 14−10=414 - 10 = 4 → linear with d=4d = 4.
  2. Rule: 4n+(6−4)=4n+24n + (6 - 4) = 4n + 2.
  3. For n=25n = 25: 4(25)+2=1024(25) + 2 = 102.

Answer: 102 people.

Trick / memory aid

Find the “zeroth term”: step back once from the first term by subtracting dd. That number is the constant in the rule.

Common mistakes
  • Using the first term as the constant (writing 4n+64n + 6). Always check the rule with n=1n = 1.
  • Calling 1, 2, 4, 8 linear just because it increases — the differences 1, 2, 4 are not constant.

4Linear growth and linear decay

Linear growth means a quantity increases by the same fixed amount in each unit of time: V=(start)+(rate)×tV = (\text{start}) + (\text{rate}) \times t, with a positive rate.

Linear decay means it decreases by the same fixed amount each unit: the rate is negative. A scooter bought for ₹80,000 that loses ₹6,000 of value every year has value V=80000−6000tV = 80000 - 6000t.

Not every change is linear. If something grows by the same percentage each year (like compound interest or bacteria doubling), the amount added keeps changing — that is not linear. Real models also have limits: the scooter's value cannot go below zero.

Key formulas & definitions
  • Growth: V(t)=V0+rtV(t) = V_0 + rt, r>0r > 0 · Decay: V(t)=V0−rtV(t) = V_0 - rt, r>0r > 0
  • V0V_0 = starting value (value at t=0t = 0); rr = change per unit time.
Worked example 1

A prepaid metro card has ₹450. Each trip costs ₹30. After how many trips will the balance be ₹90? When does it run out?

  1. Balance after tt trips: B=450−30tB = 450 - 30t.
  2. 450−30t=90⇒30t=360⇒t=12450 - 30t = 90 \Rightarrow 30t = 360 \Rightarrow t = 12.
  3. Runs out when 450−30t=0⇒t=15450 - 30t = 0 \Rightarrow t = 15.

Answer: After 12 trips; it runs out after 15 trips.

Common mistakes
  • Treating a percentage change as linear.
  • Forgetting that the model only makes sense for a range of values (time cannot be negative; a balance cannot go below zero).

5Linear relationships and their graphs

A relationship y=ax+by = ax + b links two quantities so that yy changes by aa whenever xx increases by 1. Plotting its pairs (x,y)(x, y) always gives a straight line.

The number aa controls the steepness and direction (the slope): a>0a > 0 rises from left to right, a<0a < 0 falls, and a bigger ∣a∣|a| means a steeper line. The number bb is the y-intercept — where the line cuts the y-axis, since x=0x = 0 gives y=by = b.

If you know two points of a linear relationship, you can find aa and bb: a=y2−y1x2−x1a = \dfrac{y_2 - y_1}{x_2 - x_1}, then substitute one point to get bb. Temperature conversion is a classic example.

Key formulas & definitions
  • Slope: a=change in ychange in x=y2−y1x2−x1a = \dfrac{\text{change in } y}{\text{change in } x} = \dfrac{y_2 - y_1}{x_2 - x_1}
  • y-intercept: bb (the value of yy when x=0x = 0).
  • Lines with the same aa are parallel; lines with the same bb meet the y-axis at the same point.
Worked example 1

Water freezes at 0 °C = 32 °F and boils at 100 °C = 212 °F. Assuming F=aC+bF = aC + b, find aa and bb, then convert 37 °C.

  1. a=212−32100−0=180100=1.8a = \dfrac{212 - 32}{100 - 0} = \dfrac{180}{100} = 1.8.
  2. At C=0C = 0, F=32F = 32, so b=32b = 32. Thus F=1.8C+32F = 1.8C + 32.
  3. F=1.8×37+32=66.6+32=98.6F = 1.8 \times 37 + 32 = 66.6 + 32 = 98.6.

Answer: F=1.8C+32F = 1.8C + 32; 37 °C = 98.6 °F.

Trick / memory aid

To sketch y=ax+by = ax + b fast: mark (0,b)(0, b), then from there go 1 right and aa up (or down if aa is negative). Join the two points.

Common mistakes
  • Mixing up slope and intercept — in y=2x+5y = 2x + 5, the line meets the y-axis at 5, not 2.
  • Plotting only one point; a line needs at least two (use a third as a check).

Important questions

Try each question on paper first, then tap it to check the answer.

Basic Recall and direct use

Write the degree and the constant term of 7−x+4x27 - x + 4x^2.Answer
Degree 2 (highest power is x2x^2); constant term 7.
Find p(−2)p(-2) if p(x)=4x+9p(x) = 4x + 9.Answer
p(−2)=4(−2)+9=−8+9=1p(-2) = 4(-2) + 9 = -8 + 9 = 1.
Find the zero of 34x−6\dfrac{3}{4}x - 6.Answer
34x=6⇒x=6×43=8\dfrac{3}{4}x = 6 \Rightarrow x = 6 \times \dfrac{4}{3} = 8.

Medium Two or three steps

The pattern 11, 17, 23, 29, … continues. Write the rule for the nnth term and find the 40th term.Answer
Difference 6, so the rule is 6n+(11−6)=6n+56n + (11 - 6) = 6n + 5. 40th term =6(40)+5=245= 6(40) + 5 = 245.
A candle 30 cm long burns down 2.5 cm every hour. Write its length LL after tt hours and find when it is 10 cm long.Answer
L=30−2.5tL = 30 - 2.5t. 30−2.5t=10⇒2.5t=20⇒t=830 - 2.5t = 10 \Rightarrow 2.5t = 20 \Rightarrow t = 8 hours.
A line passes through (2,7)(2, 7) and (5,16)(5, 16). Find its equation in the form y=ax+by = ax + b.Answer
a=16−75−2=3a = \dfrac{16 - 7}{5 - 2} = 3. Using (2,7)(2, 7): 7=3(2)+b⇒b=17 = 3(2) + b \Rightarrow b = 1. So y=3x+1y = 3x + 1.

Advanced Reasoning and HOTS

Taxi A charges ₹50 + ₹12 per km. Taxi B charges ₹20 + ₹15 per km. For what distance do they cost the same, and which is cheaper for a 15 km ride?Answer
50+12d=20+15d⇒30=3d⇒d=1050 + 12d = 20 + 15d \Rightarrow 30 = 3d \Rightarrow d = 10 km (both ₹170). For 15 km: A = 50+180=23050 + 180 = 230, B = 20+225=24520 + 225 = 245. A is cheaper beyond 10 km because its per-km rate is lower.
A population of a town is 12,000 and rises by 4% every year. Is this linear growth? Explain with the first two years.Answer
No. Year 1 adds 4% of 12,000 = 480 (total 12,480). Year 2 adds 4% of 12,480 = 499.2. The amount added changes, so the differences are not constant. Linear growth needs a fixed amount, not a fixed percentage.

Self-check quiz

Five quick questions. Tap an option to see if you are right.

Which of these is a linear polynomial?
The zero of 4x−104x - 10 is
In y=−3x+7y = -3x + 7, the line
The pattern 5, 9, 13, 17, … has nnth term
A bank balance increases by 5% each year. This is

FAQ

Why does the book call them 'linear' polynomials?

Because the graph of y=ax+by = ax + b is always a straight line. Degree 1 and 'straight line' go together.

Can a linear polynomial have no zero or two zeros?

No. Since a≠0a \neq 0, the equation ax+b=0ax + b = 0 always has exactly one solution, x=−b/ax = -b/a.

How do I know if a table of values is linear?

Check that xx goes up in equal steps and the yy-values change by the same amount each step. If the differences are constant, the relationship is linear.

Book references

  • NCERT Ganita Manjari Part I, Chapter 2: Introduction to Linear PolynomialsRead the chapter and do every exercise set first.
  • Mathematics for Class 9 — R.D. Sharma (Dhanpat Rai)Extra graded practice; its chapter numbers follow the old syllabus, so match by topic.
  • Mathematics for Class 9 — R.S. Aggarwal (Bharati Bhawan)Good for drill on basics; match by topic.
  • Exemplar Problems in Mathematics, Class IX — NCERTHarder, concept-testing questions (written for the old book).

These notes, examples and questions are written by PrepRung in our own words to help you study the NCERT Ganita Manjari book. NCERT and CBSE are not affiliated with PrepRung. Always study from your textbook too.