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Class 9 Maths Chapter 9: Propositions and their Converses — Notes, Examples & Practice

Mathematics runs on statements that are either true or false, and on careful reasons for deciding which. This chapter teaches you to read an 'if X, then Y' statement, flip it into its converse, and judge each one: prove it with a general argument, or break it with a single counterexample. You will apply these ideas to numbers and to geometry, including the converse of the Baudhāyana–Pythagoras theorem.

1Propositions and if–then statements

A proposition is a sentence that is definitely true or false, not both. '7 is a prime number' is a proposition (true). '12 is odd' is a proposition (false). 'Close the door' and 'Is it raining?' are not propositions.

Many mathematical propositions have the form 'If X, then Y', written X⇒YX \Rightarrow Y and read 'X implies Y'. X is the hypothesis (what we assume) and Y the conclusion. It claims that whenever X is true, Y is true as well.

Statements can be reworded into this form: 'Every multiple of 6 is a multiple of 3' means 'If a number is a multiple of 6, then it is a multiple of 3'.

Key formulas & definitions
  • Proposition: a statement with a definite truth value.
  • X⇒YX \Rightarrow Y: whenever X holds, Y holds.
  • X⇒YX \Rightarrow Y is false only when X is true and Y is false.
Worked example 1

Rewrite in if–then form and decide if true: 'A square has equal diagonals.'

  1. If–then: 'If a quadrilateral is a square, then its diagonals are equal.'
  2. True: in a square ABCD, triangles ABC and BAD are congruent (SAS), so AC=BDAC = BD.

Answer: If a quadrilateral is a square, then its diagonals are equal — true.

Common mistakes
  • Treating opinions ('Maths is fun') as propositions — they have no definite truth value.

2The converse of a statement

The converse of 'If X, then Y' is 'If Y, then X' — the hypothesis and conclusion swap places.

A true statement can have a false converse. 'If it is raining, the road is wet' is true, but 'If the road is wet, it is raining' is false — someone may have washed it. Similarly 'If nn is a multiple of 6, then it is a multiple of 3' is true, but its converse fails at n=9n = 9.

So you must judge a converse separately. Never assume it is true because the original is.

Key formulas & definitions
  • Statement: X⇒YX \Rightarrow Y · Converse: Y⇒XY \Rightarrow X
  • Truth of one says nothing about the truth of the other.
Worked example 1

Write the converse and judge both: 'If two triangles are congruent, then they have equal areas.'

  1. Original: congruent triangles fit exactly on each other, so their areas are equal — true.
  2. Converse: 'If two triangles have equal areas, then they are congruent.'
  3. Counterexample: a triangle with base 6 and height 2, and one with base 4 and height 3 — both have area 6 but different shapes.

Answer: Original true; converse false.

Trick / memory aid

To write a converse, physically swap the two chunks of the sentence after 'if' and after 'then'. Keep the wording otherwise identical.

Common mistakes
  • Confusing the converse with the negation ('if not X, then not Y').

3Counterexamples

A claim about all cases is disproved by one case where it fails — a counterexample. To disprove 'Every prime is odd', the single example 2 is enough.

But a claim about all cases is not proved by checking a few examples, however many. n2+n+41n^2 + n + 41 gives primes for n=0,1,…,39n = 0, 1, \dots, 39, yet at n=40n = 40 it equals 402+40+41=41240^2 + 40 + 41 = 41^2, not prime.

History has a famous case: Fermat claimed every number 22n+12^{2^n} + 1 is prime. It is for n=0n = 0 to 4 (3, 5, 17, 257, 65537), but Euler showed 232+1=641×67004172^{32} + 1 = 641 \times 6700417.

Key formulas & definitions
  • One counterexample disproves a universal claim.
  • Examples alone never prove a universal claim — you need a general argument.
Worked example 1

Prove or disprove: 'If nn is a natural number, then 4n2+14n^2 + 1 is prime.'

  1. Try values: n=1n = 1: 5 ✓, n=2n = 2: 17 ✓, n=3n = 3: 37 ✓, n=4n = 4: 65 = 5 × 13 ✗.

Answer: False; n=4n = 4 is a counterexample.

Worked example 2

Prove: 'If a number's last three digits form a number divisible by 8, then the number is divisible by 8.'

  1. Write the number as N=1000k+mN = 1000k + m, where mm is the number formed by the last three digits.
  2. 1000=8×1251000 = 8 \times 125, so 1000k1000k is divisible by 8.
  3. If 8 divides mm, then 8 divides 1000k+m=N1000k + m = N.

Answer: Proved for every number, not just examples.

Common mistakes
  • Saying 'it worked for 1, 2, 3 so it is always true'.
  • Offering a counterexample that does not actually satisfy the hypothesis.

4When both directions hold

Sometimes a statement and its converse are both true. Then X and Y are equivalent, written X⇔YX \Leftrightarrow Y and read 'X if and only if Y'.

Example: 'A positive integer is a perfect square if and only if it has an odd number of factors.' Why: factors come in pairs (d,nd)(d, \dfrac{n}{d}). The pairs always contribute an even count — except when d=ndd = \dfrac{n}{d}, i.e. d2=nd^2 = n, which happens only for perfect squares. So 36 has factors 1, 2, 3, 4, 6, 9, 12, 18, 36 (nine of them, because 6 pairs with itself).

Not every 'nice' converse works: x3=y3⇒x=yx^3 = y^3 \Rightarrow x = y is true for real numbers, but x2=y2⇒x=yx^2 = y^2 \Rightarrow x = y is false (x=3x = 3, y=−3y = -3).

Key formulas & definitions
  • X⇔YX \Leftrightarrow Y means X⇒YX \Rightarrow Y and Y⇒XY \Rightarrow X.
  • To prove 'if and only if', prove both directions.
Worked example 1

Is this an 'if and only if': 'A number is divisible by 3 if the sum of its digits is divisible by 3'?

  1. Any number N=100a+10b+c=99a+9b+(a+b+c)N = 100a + 10b + c = 99a + 9b + (a + b + c).
  2. 99a+9b99a + 9b is always a multiple of 3, so NN and a+b+ca + b + c leave the same remainder on division by 3.
  3. So 3 divides NN exactly when 3 divides the digit sum — both directions hold (the argument works for any number of digits).

Answer: Yes, it is an 'if and only if'.

Common mistakes
  • Proving only one direction and claiming 'if and only if'.

5Converses in geometry

Baudhāyana–Pythagoras theorem: if a triangle has a right angle, then the square on the hypotenuse equals the sum of the squares on the other two sides (a2+b2=c2a^2 + b^2 = c^2). Baudhāyana's Śulba-sūtra stated this for rope constructions of altars.

Its converse is also true: if the sides of a triangle satisfy a2+b2=c2a^2 + b^2 = c^2, then the angle opposite cc is 90∘90^\circ. Proof idea: build a right triangle with legs aa and bb; its hypotenuse is a2+b2=c\sqrt{a^2 + b^2} = c. The two triangles have the same three sides, so they are congruent by SSS, and the original angle must be 90∘90^\circ too.

Isosceles triangle theorem: if two sides are equal, the angles opposite them are equal. Converse (true): if two angles are equal, the sides opposite them are equal. Proof idea: draw the bisector (or the perpendicular) from the third vertex and use AAS congruence.

Key formulas & definitions
  • a2+b2=c2⇔a^2 + b^2 = c^2 \Leftrightarrow the angle opposite cc is 90∘90^\circ.
  • In a triangle: equal sides ⇔\Leftrightarrow equal opposite angles.
  • Congruence tests: SSS, SAS, ASA, AAS, RHS. (SSA is not a test.)
Worked example 1

Is a triangle with sides 7, 24 and 25 right-angled?

  1. Longest side 25: 252=62525^2 = 625.
  2. 72+242=49+576=6257^2 + 24^2 = 49 + 576 = 625.
  3. Equal, so by the converse of Pythagoras the angle opposite 25 is a right angle.

Answer: Yes.

Common mistakes
  • Checking a2+b2=c2a^2 + b^2 = c^2 with cc not the longest side.
  • Using the theorem (not the converse) to conclude that an angle is 90∘90^\circ.

Important questions

Try each question on paper first, then tap it to check the answer.

Basic Recall and direct use

Which are propositions? (a) 5+3=95 + 3 = 9 (b) Please sit down. (c) Every square is a rectangle.Answer
(a) is a proposition (false). (b) is not. (c) is a proposition (true).
Write the converse of: 'If a number ends in 0, then it is divisible by 5.' Is the converse true?Answer
Converse: 'If a number is divisible by 5, then it ends in 0.' False — 15 is divisible by 5 but ends in 5.
Give a counterexample to: 'The sum of two prime numbers is always even.'Answer
2+3=52 + 3 = 5, which is odd.

Medium Two or three steps

Prove or disprove: 'If x2>4x^2 > 4, then x>2x > 2.'Answer
False. x=−3x = -3: x2=9>4x^2 = 9 > 4 but x<2x < 2.
State the converse of 'If a quadrilateral is a rectangle, then its diagonals are equal.' Is it true?Answer
Converse: 'If a quadrilateral has equal diagonals, then it is a rectangle.' False — an isosceles trapezium has equal diagonals but is not a rectangle.
Show that the sides 9, 40, 41 form a right triangle and say which angle is the right angle.Answer
92+402=81+1600=1681=4129^2 + 40^2 = 81 + 1600 = 1681 = 41^2. The right angle is opposite the side of length 41.

Advanced Reasoning and HOTS

Prove: 'If nn is odd, then n2n^2 is odd.' Then state and prove its converse.Answer
Odd n=2k+1n = 2k + 1, so n2=4k2+4k+1=2(2k2+2k)+1n^2 = 4k^2 + 4k + 1 = 2(2k^2 + 2k) + 1, odd. Converse: 'If n2n^2 is odd, then nn is odd.' Suppose not: nn even, n=2kn = 2k, so n2=4k2n^2 = 4k^2 is even — contradiction. So the converse is true; nn odd ⇔\Leftrightarrow n2n^2 odd.
Explain with a sketch why 'two sides and a non-included angle' (SSA) does not guarantee congruence.Answer
Take ∠B=30∘\angle B = 30^\circ, AB=10AB = 10 and AC=6AC = 6. Draw ray BC; with centre A and radius 6 the arc cuts the ray at two points C1C_1 and C2C_2. Triangles ABC1ABC_1 and ABC2ABC_2 both have AB=10AB = 10, AC=6AC = 6, ∠B=30∘\angle B = 30^\circ but are clearly different. So SSA can give two triangles.

Self-check quiz

Five quick questions. Tap an option to see if you are right.

The converse of 'If P, then Q' is
To disprove 'all odd numbers are prime', you need
Which number has an odd number of factors?
A triangle has sides 8, 15, 17. It is
Which statement has a FALSE converse?

FAQ

Is the converse the same as the 'opposite' of a statement?

No. The converse swaps the parts (Y ⇒ X). The negation says the statement is false. They are different ideas.

How many counterexamples do I need to show a statement is false?

Just one, as long as it satisfies the 'if' part and fails the 'then' part.

Why is this chapter in maths?

Every theorem — in geometry, algebra or number theory — is a proposition. Knowing how to state, prove and test converses is what makes mathematical arguments reliable.

Book references

  • NCERT Ganita Manjari Part II, Chapter 9: Propositions and their ConversesRead the chapter and do every exercise set first.
  • Mathematics for Class 9 — R.D. Sharma (Dhanpat Rai)Extra graded practice; its chapter numbers follow the old syllabus, so match by topic.
  • Mathematics for Class 9 — R.S. Aggarwal (Bharati Bhawan)Good for drill on basics; match by topic.
  • Exemplar Problems in Mathematics, Class IX — NCERTHarder, concept-testing questions (written for the old book).

These notes, examples and questions are written by PrepRung in our own words to help you study the NCERT Ganita Manjari book. NCERT and CBSE are not affiliated with PrepRung. Always study from your textbook too.