CAT 2025 · Slot 1
A full-length paper in the 2025 pattern. Sit it under exam conditions with solutions locked until you submit, or open it in learn mode and check each answer as you go.
68questions
120 min40 min per section
22TITA, no negative marks
17/35/16easy / medium / hard
Section-wise pattern and topics
Sections run in this order with their own timer, as in CAT 2025.
Verbal Ability & Reading Comprehension · 24 questions · 40 min
- Reading Comprehension16
- Para Summary2
- Para Jumble2
- Odd Sentence Out2
- Para Placement2
Data Interpretation & Logical Reasoning · 22 questions · 40 min
- tables6
- tournaments/rankings6
- optimal assignment5
- rates/network flow5
Quantitative Ability · 22 questions · 40 min
- Simple & Compound Interest2
- Profit, Loss & Discount1
- Mixtures & Alligation1
- Time & Work1
- Time, Speed & Distance1
- Averages1
- Ratio, Proportion & Partnership1
- Percentages1
- Quadratic Equations1
- Linear Equations1
- Inequalities1
- Functions1
- Progressions (AP/GP)1
- Logarithms1
- Triangles1
- Circles1
- Mensuration1
- Coordinate Geometry1
- Number System1
- Permutation & Combination1
- Probability1
Sample question from this paper
Time & Work · medium
A can complete a job in 18 days and B can complete the same job in 24 days. They start working together, but A leaves after 6 days. In how many more days will B alone finish the remaining work?
- A. 14
- B. 15
- C. 16
- D. 18
Show answer and solution
Answer: C
A's 1-day rate = 1/18, B's = 1/24. Work done by A in 6 days = 6/18 = 1/3. Remaining work = 2/3. Time for B to finish 2/3 alone = (2/3)/(1/24) = 16 days. So B alone needs 16 more days after A leaves (total time from start would be 6+16 = 22 days).
A's 1-day rate = 1/18, B's = 1/24. Work done by A in 6 days = 6/18 = 1/3. Remaining work = 2/3. Time for B to finish 2/3 alone = (2/3)/(1/24) = 16 days. So B alone needs 16 more days after A leaves (total time from start would be 6+16 = 22 days).