Home / JEE Advanced / 2020 Paper 1

JEE Advanced 2020 · Paper 1

A full paper in the 2020 Paper 1 pattern: Physics, Chemistry and Mathematics, 18 questions each, one 180-minute clock. Take it as a timed mock or open it in learn mode and check every answer.

54questions

180 minone clock

198maximum marks

2/32/20easy / medium / hard

Start timed mock Study with solutions

Sections and marking

Each subject has the same 3 sections, 66 marks per subject.

Section	Type	Questions	Marking
Section 1	Single correct	6	+3 / -1
Section 2	One or more correct	6	+4 all correct, partial +3/+2/+1, -2 otherwise
Section 3	Numerical value	6	+4, no negative

Topics in this paper

Physics · 18 questions

Rolling motion + projectile1
Thermodynamic cycles1
Capacitors with dielectrics1
Newton's rings1
Bohr model + photoelectric effect1
Electromagnetic induction + dynamics1
Fluid dynamics (Torricelli)1
Doppler effect + resonance in pipes1
RC circuits1
Rotational dynamics1
Heat conduction1
Gravitation (orbits)1
Errors and experiments1
Collisions + SHM1

Chemistry · 18 questions

Electrochemistry and solubility equilibrium1
Hydroboration, oxidation and enolisation1
Coordination compounds1
Chemical kinetics with total pressure1
Beckmann rearrangement and diazotisation1
p-block1
Thermodynamics1
Chemical bonding1
Isomerism1
d-block1
Solutions1
Nucleophilic substitution and rearrangement1
Kinetics of SN2 racemisation1
Ionic equilibrium1

Mathematics · 18 questions

Complex numbers2
Permutations and combinations2
Matrices1
Probability1
Limits and integrals1
Area under curves1
3D geometry1
Functions1
Theory of equations1
Differential equations1
Ellipse1
Trigonometric equations1
Circles1
Vectors and 3D geometry1

Sample question from this paper

Mathematics · Functions: continuity and differentiability · one or more options correct

Let

f(x)=|x^{2}-1|+|x-2|

for

x\in\mathbb R

. Which of the following statements is/are correct?

A. $f$ is not differentiable at exactly three points
B. The minimum value of $f$ on $\mathbb R$ is $1$
C. $\displaystyle\int_0^3 f(x)\,dx=10$
D. $f$ is differentiable at $x=0$ and $f'(0)=1$

Show answer and solution

Answer: A, B
The kinks come from

x=\pm1

(zeros of

x^2-1

, simple zeros) and

x=2

, so there are exactly three points of non-differentiability; (A) is true. On

[-1,1]

f=3-x-x^2

(decreasing to

1

x=1

); on

[1,2]

f=x^2-x+1\ge1

with minimum at

x=1

; for

x\ge2

and

x\le-1

the values exceed

3

or are larger. So the minimum is

f(1)=1

and (B) is true. Integrating piecewise,

\int_0^1(3-x-x^2)dx=\tfrac{13}{6}

\int_1^2(x^2-x+1)dx=\tfrac{11}{6}

\int_2^3(x^2+x-3)dx=\tfrac{35}{6}

, total

\tfrac{59}{6}\ne10

; (C) is false. Near

0

f=3-x-x^2

, so

f'(0)=-1

, not

1

; (D) is false.

Other papers

JEE Advanced 2020 Paper 2 2025 Paper 1 2024 Paper 1 2023 Paper 1 2022 Paper 1 2021 Paper 1 2019 Paper 1 2018 Paper 1 2017 Paper 1 2016 Paper 1 All JEE Advanced papers