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JEE Advanced 2017 Paper 1 · Physics · Magnetic Effects of Current · medium

Two smooth parallel metal rails, 0.5 m apart, are inclined at 30^° to the horizontal and joined at the bottom by a resistor R=2 Ω. A uniform magnetic…

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Two smooth parallel metal rails, 0.5 m0.5\ \mathrm{m} apart, are inclined at 30∘30^\circ to the horizontal and joined at the bottom by a resistor R=2 ΩR=2\ \Omega. A uniform magnetic field B=0.8 TB=0.8\ \mathrm{T} is perpendicular to the plane of the rails. A rod of mass 0.1 kg0.1\ \mathrm{kg} and negligible resistance, kept perpendicular to the rails, is released from rest and slides down with good contact. Take g=10 m s−2g=10\ \mathrm{m\,s^{-2}}. Which of the following statements is/are correct?
  1. A. The terminal speed of the rod is 6.25 m s−16.25\ \mathrm{m\,s^{-1}}.
  2. B. When its speed is 3.125 m s−13.125\ \mathrm{m\,s^{-1}}, the acceleration of the rod is 2.5 m s−22.5\ \mathrm{m\,s^{-2}}.
  3. C. At terminal speed the power dissipated in the resistor is 3.125 W3.125\ \mathrm{W}.
  4. D. The speed of the rod after 1.25 s1.25\ \mathrm{s} is 4.5 m s−14.5\ \mathrm{m\,s^{-1}}.
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Answer: A, B, C

The motional emf is BlvBlv, the current Blv/RBlv/R, and the magnetic retarding force B2l2v/RB^2l^2v/R acts up the incline. So mv˙=mgsin⁡θ−B2l2Rvm\dot v=mg\sin\theta-\dfrac{B^2l^2}{R}v. With B2l2=0.16B^2l^2=0.16, terminal speed is vT=mgRsin⁡θB2l2=0.1×10×2×0.50.16=6.25 m s−1v_T=\dfrac{mgR\sin\theta}{B^2l^2}=\dfrac{0.1\times10\times2\times0.5}{0.16}=6.25\ \mathrm{m\,s^{-1}} (A true). At half of vTv_T the magnetic force is half of mgsin⁡θmg\sin\theta, so a=12gsin⁡θ=2.5 m s−2a=\tfrac12g\sin\theta=2.5\ \mathrm{m\,s^{-2}} (B true). At terminal speed the power dissipated equals the power of gravity, mgsin⁡θ vT=0.5×6.25=3.125 Wmg\sin\theta\,v_T=0.5\times6.25=3.125\ \mathrm{W} (C true). The time constant is τ=mR/B2l2=1.25 s\tau=mR/B^2l^2=1.25\ \mathrm{s} and v(t)=vT(1−e−t/τ)v(t)=v_T\left(1-e^{-t/\tau}\right), so v(1.25)=6.25(1−e−1)≈3.95 m s−1v(1.25)=6.25(1-e^{-1})\approx3.95\ \mathrm{m\,s^{-1}}, not 4.54.5 (D false). Correct options: A, B and C.
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