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JEE Advanced 2023 Paper 2 · Mathematics · Vector Algebra · medium

Let vec u,vec v,vec w be unit vectors such that the angle between every two of them is 60^°. The volume of the parallelepiped whose coterminous edges…

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Let u⃗,v⃗,w⃗\vec u,\vec v,\vec w be unit vectors such that the angle between every two of them is 60∘60^\circ. The volume of the parallelepiped whose coterminous edges are u⃗+v⃗, v⃗+w⃗, w⃗+u⃗\vec u+\vec v,\ \vec v+\vec w,\ \vec w+\vec u is
  1. A. 3\sqrt3
  2. B. 12\dfrac{1}{\sqrt2}
  3. C. 2\sqrt2
  4. D. 222\sqrt2
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Answer: (C) 2\sqrt2

The Gram matrix of u⃗,v⃗,w⃗\vec u,\vec v,\vec w is G=(112121211212121)G=\begin{pmatrix}1&\frac12&\frac12\\ \frac12&1&\frac12\\ \frac12&\frac12&1\end{pmatrix} with det⁡G=12\det G=\frac12, and [u⃗ v⃗ w⃗]2=det⁡G[\vec u\,\vec v\,\vec w]^2=\det G, so ∣[u⃗ v⃗ w⃗]∣=12|[\vec u\,\vec v\,\vec w]|=\frac1{\sqrt2}. Now [u⃗+v⃗,v⃗+w⃗,w⃗+u⃗]=2[u⃗ v⃗ w⃗][\vec u+\vec v,\vec v+\vec w,\vec w+\vec u]=2[\vec u\,\vec v\,\vec w] (the coefficient matrix has determinant 22). Volume =22=2=\frac{2}{\sqrt2}=\sqrt2. A numerical construction with a Cholesky factor of GG confirms this. The option 12\frac1{\sqrt2} forgets the factor 22.
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