CAT 2024 · Slot 1
A full-length paper in the 2024 pattern. Sit it under exam conditions with solutions locked until you submit, or open it in learn mode and check each answer as you go.
68questions
120 min40 min per section
19TITA, no negative marks
17/36/15easy / medium / hard
Section-wise pattern and topics
Sections run in this order with their own timer, as in CAT 2024.
Verbal Ability & Reading Comprehension · 24 questions · 40 min
- Reading Comprehension16
- Para Summary2
- Para Jumble2
- Odd Sentence Out2
- Sentence Placement2
Data Interpretation & Logical Reasoning · 22 questions · 40 min
- Tournaments6
- Scheduling5
- Puzzles5
- Tables4
- Percentages2
Quantitative Ability · 22 questions · 40 min
- Percentages2
- Mixtures & Alligation2
- Simple & Compound Interest1
- Profit & Loss1
- Averages1
- Time, Speed & Distance1
- Time & Work1
- Linear Equations1
- Inequalities1
- Functions1
- Logarithms1
- Progressions1
- Quadratic Equations1
- Triangles1
- Circles1
- Solids1
- Coordinate Geometry1
- Number System1
- Permutations & Combinations1
- Probability1
Sample question from this paper
Mixtures & Alligation · medium
Alloy A contains copper and zinc in the ratio 3:2, and alloy B contains them in the ratio 1:3. If equal quantities (by weight) of A and B are melted together to form alloy C, find the ratio of copper to zinc in C.
- A. 3:4
- B. 17:23
- C. 19:21
- D. 1:1
Show answer and solution
Answer: B
Take 20 units of each alloy (LCM of 5 and 4). In A: copper = (3/5)×20 = 12, zinc = 8. In B: copper = (1/4)×20 = 5, zinc = 15. In C: total copper = 12+5 = 17, total zinc = 8+15 = 23. Ratio = 17:23, which does not simplify further.
Take 20 units of each alloy (LCM of 5 and 4). In A: copper = (3/5)×20 = 12, zinc = 8. In B: copper = (1/4)×20 = 5, zinc = 15. In C: total copper = 12+5 = 17, total zinc = 8+15 = 23. Ratio = 17:23, which does not simplify further.