Single correct option
ABCD is a square of side 10 cm. E is the midpoint of AB and F is the midpoint of BC. The segments DE and AF intersect at G. What is the area of triangle ADG (in cm²)?
- A. 16
- B. 20
- C. 25
- D. 30
Show answer and solution
Answer: (B) 20
Place A(0, 0), B(10, 0), C(10, 10), D(0, 10). Then E = (5, 0) and F = (10, 5).
Line DE: through (0, 10) and (5, 0), so y = 10 − 2x.
Line AF: through (0, 0) and (10, 5), so y = x/2.
Intersection: x/2 = 10 − 2x gives x = 4, y = 2. So G = (4, 2).
Triangle ADG has base AD = 10 on the y-axis, and its height is the x-coordinate of G, which is 4.
Area = ½ × 10 × 4 = 20.
Note: DE ⟂ AF (slopes −2 and 1/2). This is the well-known perpendicular-segments configuration in a square.
Line DE: through (0, 10) and (5, 0), so y = 10 − 2x.
Line AF: through (0, 0) and (10, 5), so y = x/2.
Intersection: x/2 = 10 − 2x gives x = 4, y = 2. So G = (4, 2).
Triangle ADG has base AD = 10 on the y-axis, and its height is the x-coordinate of G, which is 4.
Area = ½ × 10 × 4 = 20.
Note: DE ⟂ AF (slopes −2 and 1/2). This is the well-known perpendicular-segments configuration in a square.
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