PrepRung

JEE Advanced 2025 Paper 1 · Mathematics · Conic Sections · hard

Let PQ be the focal chord of the parabola y^2=8x with P=(8,8), where F is the focus.

One or more options correct

Let PQPQ be the focal chord of the parabola y2=8xy^{2}=8x with P=(8,8)P=(8,8), where FF is the focus. Which of the following statements is/are correct?
  1. A. PQ=252PQ=\dfrac{25}{2}
  2. B. The area of △OPQ\triangle OPQ is 1212, where OO is the origin
  3. C. The circle with PQPQ as diameter touches the line x=−2x=-2
  4. D. The tangents to the parabola at PP and QQ are perpendicular
Show answer and solution

Answer: A, C, D

The parabola y2=8xy^2=8x has a=2a=2, focus F(2,0)F(2,0) and directrix x=−2x=-2; points are (2t2,4t)(2t^2,4t). PP corresponds to t=2t=2. For a focal chord the parameters satisfy tt′=−1tt'=-1, so t′=−12t'=-\frac12 and Q=(12,−2)Q=(\frac12,-2). (A) True: the focal chord length is xP+xQ+2a=8+12+4=252x_P+x_Q+2a=8+\frac12+4=\frac{25}{2}. (B) False: the area of △OPQ\triangle OPQ is 12∣8(−2)−12⋅8∣=12⋅20=10\frac12|8(-2)-\frac12\cdot8|=\frac12\cdot20=10, not 1212. (C) True: the circle on PQPQ as diameter has centre (174,3)\left(\frac{17}{4},3\right) and radius 254\frac{25}{4}; its distance from the line x=−2x=-2 is 174+2=254\frac{17}{4}+2=\frac{25}{4}, so it touches the directrix (a general property for focal chords). (D) True: tangent slopes at parameter tt is 1t\frac1t, so they are 12\frac12 and −2-2, whose product is −1-1, hence the tangents at PP and QQ are perpendicular (and meet on the directrix). Correct options: A, C, D.
Report a mistake

Original question written in the JEE Advanced 2025 Paper 1 pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake