Single correct option
Consider the ellipse . Match the quantities in List-I with the values in List-II.
List-I
(P) The product of the perpendicular distances from the two foci of to a variable tangent of .
(Q) The radius of the circle that is the locus of the foot of the perpendicular drawn from a focus of to a variable tangent.
(R) The square of the radius of the director circle of (the locus of points from which two perpendicular tangents can be drawn to ).
(S) The least area of the triangle formed by a tangent to at a point in the first quadrant and the coordinate axes.
List-II
(1)
(2)
(3)
(4)
(5)
List-I
(P) The product of the perpendicular distances from the two foci of to a variable tangent of .
(Q) The radius of the circle that is the locus of the foot of the perpendicular drawn from a focus of to a variable tangent.
(R) The square of the radius of the director circle of (the locus of points from which two perpendicular tangents can be drawn to ).
(S) The least area of the triangle formed by a tangent to at a point in the first quadrant and the coordinate axes.
List-II
(1)
(2)
(3)
(4)
(5)
- A. P→2, Q→3, R→4, S→1
- B. P→2, Q→3, R→1, S→4
- C. P→5, Q→3, R→4, S→1
- D. P→2, Q→4, R→3, S→1
Show answer and solution
Answer: (A) P→2, Q→3, R→4, S→1
The foci are since . (P) For the tangent the two focal distances multiply to , which is (2). (Q) The foot of the perpendicular from a focus to any tangent lies on the auxiliary circle , of radius , which is (3). (R) The director circle is , so the square of its radius is , which is (4). (S) The tangent has intercepts and , so the triangle area is , which is (1). Hence P→2, Q→3, R→4, S→1. Numerical checks with random tangents confirmed the product , the radius , perpendicular slopes at a point on the circle , and the minimum area . The value (5) is a distractor.
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