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JEE Main 2022 · Chemistry · Coordination Compounds · hard

Among [Ni(CN)4]^2-, [NiCl4]^2-, Ni(CO)4, [Fe(CN)6]^3-, [Co(NH3)6]^3+ and [CoF6]^3-, the number of complexes that are diamagnetic and also use the…

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Among [Ni(CN)4]2−\mathrm{[Ni(CN)_4]^{2-}}, [NiCl4]2−\mathrm{[NiCl_4]^{2-}}, Ni(CO)4\mathrm{Ni(CO)_4}, [Fe(CN)6]3−\mathrm{[Fe(CN)_6]^{3-}}, [Co(NH3)6]3+\mathrm{[Co(NH_3)_6]^{3+}} and [CoF6]3−\mathrm{[CoF_6]^{3-}}, the number of complexes that are diamagnetic and also use the (n−1)d(n-1)d orbitals in hybridisation is
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Answer: 2

[Ni(CN)4]2−\mathrm{[Ni(CN)_4]^{2-}}: Ni2+\mathrm{Ni^{2+}} d8d^8, strong field pairing, dsp2dsp^2 square planar, diamagnetic and uses 3d3d: counts. [NiCl4]2−\mathrm{[NiCl_4]^{2-}}: sp3sp^3, two unpaired electrons: no. Ni(CO)4\mathrm{Ni(CO)_4}: Ni(0) 3d103d^{10}, sp3sp^3, diamagnetic but no dd orbital used: no. [Fe(CN)6]3−\mathrm{[Fe(CN)_6]^{3-}}: d2sp3d^2sp^3 but one unpaired electron: no. [Co(NH3)6]3+\mathrm{[Co(NH_3)_6]^{3+}}: Co3+\mathrm{Co^{3+}} d6d^6 low spin, d2sp3d^2sp^3, diamagnetic: counts. [CoF6]3−\mathrm{[CoF_6]^{3-}}: sp3d2sp^3d^2, four unpaired electrons: no. Answer 2.
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