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JEE Main 2024 · Chemistry · Coordination Compounds · medium

The total number of stereoisomers (counting enantiomers separately) of [Co(en)2Cl2]^+ together with those of the square planar complex…

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The total number of stereoisomers (counting enantiomers separately) of [Co(en)2Cl2]+[\mathrm{Co(en)_2Cl_2}]^+ together with those of the square planar complex [Pt(NH3)(py)ClBr][\mathrm{Pt(NH_3)(py)ClBr}] is (en = ethylenediamine, py = pyridine)
  1. A. 55
  2. B. 66
  3. C. 77
  4. D. 44
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Answer: (B) 66

[Co(en)2Cl2]+[\mathrm{Co(en)_2Cl_2}]^+ is octahedral of type [M(AA)2b2][M(AA)_2b_2]: the trans form is achiral (1) and the cis form has no mirror plane and exists as a pair of enantiomers (2), giving 33 stereoisomers. [Pt(abcd)][\mathrm{Pt}(abcd)] square planar has 33 geometrical isomers (fix one ligand and place each of the other three trans to it), none optically active. Total =3+3=6=3+3=6.
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