Alkenes, on reductive ozonolysis (O3 then Zn/H2O), gives a single product that answers both Tollens' test and the iodoform test?

1-Methylcyclopentene is cleaved at the ring double bond to give one open-chain compound $\mathrm{CH_3CO(CH_2)_3CHO}$ (5-oxohexanal). It has a CHO group (Tollens' positive) and a $\mathrm{CH_3CO-}$ group (iodoform positive). Cyclohexene gives hexanedial: Tollens' positive, iodoform negative. 1,2-Dimethylcyclohexene gives octane-2,7-dione: iodoform positive but no CHO. Methylenecyclohexane gives two products, cyclohexanone and methanal, so it fails the 'single product' condition and neither responds to both tests.