JEE Main 2022 · Chemistry · Solutions, Solid State and Surface Chemistry · medium

100 mL of 0.30 M glucose solution is mixed with 200 mL of 0.15 M NaCl solution (assume complete dissociation and additive volumes) at 300 K. The…

Numerical answer

100\ \mathrm{mL}

0.30\ \mathrm M

glucose solution is mixed with

200\ \mathrm{mL}

0.15\ \mathrm M

NaCl solution (assume complete dissociation and additive volumes) at

300\ \mathrm K

. The osmotic pressure of the mixture, in atm to the nearest integer (

R=0.0821\ \mathrm{L\,atm\,mol^{-1}K^{-1}}

), is

Show answer and solution

Answer: 7

Osmotic pressure depends on total particle concentration. Glucose:

0.100\times0.30=0.030

mol of particles. NaCl gives two particles per formula unit:

0.200\times0.15\times2=0.060

mol. Total

=0.090

mol in

0.300

L, giving

0.30\ \mathrm{mol\,L^{-1}}

\pi=CRT=0.30\times0.0821\times300=7.39\ \mathrm{atm}\approx7

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