Single correct option
The average of 12 numbers is 40. When two of the numbers are removed, the average of the remaining numbers becomes 38. If one of the removed numbers exceeds the other by 10, the larger of the removed numbers is
- A. 50
- B. 60
- C. 55
- D. 45
Show answer and solution
Answer: (C) 55
Total of 12 numbers = 12 × 40 = 480.
Total of remaining 10 numbers = 10 × 38 = 380.
Sum of removed numbers = 480 − 380 = 100. With difference 10, they are (100 + 10)/2 = 55 and 45.
The larger number is 55. Option 45 is the smaller one — read the question carefully.
Total of remaining 10 numbers = 10 × 38 = 380.
Sum of removed numbers = 480 − 380 = 100. With difference 10, they are (100 + 10)/2 = 55 and 45.
The larger number is 55. Option 45 is the smaller one — read the question carefully.
Saved on this device. Sign in or create a free account to keep it on every device.