Units) of the triangle formed by the lines y = x, y = −x + 8 and y = 2.

Find the pairwise intersection points. y=x and y=−x+8: x=−x+8 → x=4, so (4,4). y=x and y=2: (2,2). y=−x+8 and y=2: 2=−x+8 → x=6, so (6,2). Using the area formula for a triangle with vertices (x1,y1),(x2,y2),(x3,y3): Area = ½|x1(y2−y3)+x2(y3−y1)+x3(y1−y2)| = ½|4(2−2)+2(2−4)+6(4−2)| = ½|0−4+12| = ½(8) = 4 sq. units.