Single correct option
Find the perpendicular distance from the point (3, 4) to the line 3x − 4y + 10 = 0.
- A. 0.4
- B. 0.6
- C. 0.8
- D. 1.0
Show answer and solution
Answer: (B) 0.6
Distance from (x₀,y₀) to line ax+by+c=0 is |ax₀+by₀+c|/√(a²+b²). Here a=3, b=−4, c=10, (x₀,y₀)=(3,4). Numerator = |3×3 − 4×4 + 10| = |9−16+10| = |3| = 3. Denominator = √(9+16) = 5. Distance = 3/5 = 0.6.
Saved on this device. Sign in or create a free account to keep it on every device.