Single correct option
A function h satisfies h(x) + 4h(1/x) = 3x + 5 for every non-zero real x. What is h(2)?
- A. −1
- B. 1
- C. 2
- D. 5/2
Show answer and solution
Answer: (B) 1
Put x = 2: h(2) + 4h(1/2) = 11 … (i)
Put x = 1/2: h(1/2) + 4h(2) = 3/2 + 5 = 13/2 … (ii)
From (ii), h(1/2) = 13/2 − 4h(2). Substituting into (i): h(2) + 4(13/2 − 4h(2)) = 11 → h(2) + 26 − 16h(2) = 11 → −15h(2) = −15 → h(2) = 1.
Check: h(1/2) = 13/2 − 4 = 5/2; then 1 + 4(5/2) = 1 + 10 = 11 ✓.
Tip: Functional equations pairing x with 1/x are solved by writing the equation twice and eliminating.
Put x = 1/2: h(1/2) + 4h(2) = 3/2 + 5 = 13/2 … (ii)
From (ii), h(1/2) = 13/2 − 4h(2). Substituting into (i): h(2) + 4(13/2 − 4h(2)) = 11 → h(2) + 26 − 16h(2) = 11 → −15h(2) = −15 → h(2) = 1.
Check: h(1/2) = 13/2 − 4 = 5/2; then 1 + 4(5/2) = 1 + 10 = 11 ✓.
Tip: Functional equations pairing x with 1/x are solved by writing the equation twice and eliminating.
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