Single correct option
The sum of the first n terms of an arithmetic progression is 3n² + 5n. What is its 12th term?
- A. 68
- B. 72
- C. 74
- D. 80
Show answer and solution
Answer: (C) 74
Tₙ = Sₙ − Sₙ₋₁ = [3n² + 5n] − [3(n − 1)² + 5(n − 1)] = 6n + 2.
T₁₂ = 6 × 12 + 2 = 74.
Check: T₁ = S₁ = 8 and the common difference = 6, so T₁₂ = 8 + 11 × 6 = 74. ✓
Tip: if Sₙ = An² + Bn, then d = 2A and T₁ = A + B.
T₁₂ = 6 × 12 + 2 = 74.
Check: T₁ = S₁ = 8 and the common difference = 6, so T₁₂ = 8 + 11 × 6 = 74. ✓
Tip: if Sₙ = An² + Bn, then d = 2A and T₁ = A + B.
Saved on this device. Sign in or create a free account to keep it on every device.