Reactions is/are correctly described?

Option A: benzaldehyde has no $\alpha$-hydrogen and neither does formaldehyde; in the crossed Cannizzaro reaction the more reactive, unhindered formaldehyde adds hydroxide and donates hydride, so it is oxidised to formate, while benzaldehyde accepts the hydride and is reduced to $\mathrm{PhCH_2OH}$, so A is correct. Option B: $\mathrm{PhCOCH_3}$ is a methyl ketone, so haloform cleavage gives $\mathrm{CHI_3}$ and $\mathrm{PhCOO^-Na^+}$, and B is correct. Option C: pentan-3-one, $\mathrm{CH_3CH_2COCH_2CH_3}$, has no $\mathrm{CH_3CO}$ group (the carbonyl is flanked by ethyl groups), so it gives no iodoform; C is wrong. Option D: benzaldehyde lacks $\alpha$-hydrogens and cannot form an enolate, so it cannot undergo self aldol condensation. Cinnamaldehyde would need acetaldehyde as the enolisable partner in a crossed aldol reaction, so D is wrong.