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JEE Advanced 2017 Paper 2 · Chemistry · d- and f-Block Elements and Metallurgy · medium

Correct statement(s) about the chemistry of manganese and chromium oxoanions is(are)

One or more options correct

Correct statement(s) about the chemistry of manganese and chromium oxoanions is(are)
  1. A. In acidic medium, one mole of MnO4−\mathrm{MnO_4^-} oxidises five moles of Fe2+\mathrm{Fe^{2+}}
  2. B. In neutral medium, MnO4−\mathrm{MnO_4^-} is reduced to MnO2\mathrm{MnO_2}, accepting three electrons per ion
  3. C. In acidic solution, three moles of MnO42−\mathrm{MnO_4^{2-}} give two moles of MnO4−\mathrm{MnO_4^-} and one mole of MnO2\mathrm{MnO_2}
  4. D. Conversion of orange Cr2O72−\mathrm{Cr_2O_7^{2-}} to yellow CrO42−\mathrm{CrO_4^{2-}} on adding alkali is a redox reaction
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Answer: A, B, C

Option A is correct: MnO4−+8H++5e−→Mn2++4H2O\mathrm{MnO_4^-+8H^++5e^-\to Mn^{2+}+4H_2O}, so each permanganate accepts 5 electrons and oxidises 5 Fe2+\mathrm{Fe^{2+}} (each losing one electron). Option B is correct: MnO4−+2H2O+3e−→MnO2+4OH−\mathrm{MnO_4^-+2H_2O+3e^-\to MnO_2+4OH^-} in neutral or weakly alkaline solution, so 3 electrons are accepted. Option C is correct: manganate is stable only in strongly alkaline solution and disproportionates in acid, 3MnO42−+4H+→2MnO4−+MnO2+2H2O\mathrm{3MnO_4^{2-}+4H^+\to2MnO_4^-+MnO_2+2H_2O} (Mn +6 goes to +7 and +4; the charge is balanced as −6+4=−2-6+4=-2 on both sides). Option D is wrong: Cr2O72−+2OH−⇌2CrO42−+H2O\mathrm{Cr_2O_7^{2-}+2OH^-\rightleftharpoons2CrO_4^{2-}+H_2O} keeps chromium at +6, so it is an acid-base (pH-dependent) equilibrium, not a redox process.
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