PrepRung

JEE Advanced 2019 Paper 2 · Chemistry · d- and f-Block Elements and Metallurgy · medium

The correct statement(s) about the redox and acid-base chemistry of manganese and chromium oxoanions is(are)

One or more options correct

The correct statement(s) about the redox and acid-base chemistry of manganese and chromium oxoanions is(are)
  1. A. MnO42−\mathrm{MnO_4^{2-}} is stable in acidic solution and can be isolated from it
  2. B. In neutral medium, 22 mol of MnO4−\mathrm{MnO_4^-} (reduced to MnO2\mathrm{MnO_2}) oxidise 11 mol of I−\mathrm{I^-} to IO3−\mathrm{IO_3^-}
  3. C. The interconversion of CrO42−\mathrm{CrO_4^{2-}} and Cr2O72−\mathrm{Cr_2O_7^{2-}} with change of pH is a redox reaction
  4. D. MnO42−\mathrm{MnO_4^{2-}} is diamagnetic
Show answer and solution

Answer: B

Manganate is stable only in strongly alkaline solution; in acid it disproportionates, 3MnO42−+4H+→2MnO4−+MnO2+2H2O3\mathrm{MnO_4^{2-}}+4\mathrm{H^+}\to2\mathrm{MnO_4^-}+\mathrm{MnO_2}+2\mathrm{H_2O}, so (A) is wrong. In neutral medium MnO4−+2H2O+3e−→MnO2+4OH−\mathrm{MnO_4^-}+2\mathrm{H_2O}+3e^-\to\mathrm{MnO_2}+4\mathrm{OH^-} (3 electrons) while I−+6OH−→IO3−+3H2O+6e−\mathrm{I^-}+6\mathrm{OH^-}\to\mathrm{IO_3^-}+3\mathrm{H_2O}+6e^- (6 electrons); electron balance requires 22 permanganate per iodide, so (B) is correct. Chromate and dichromate both contain Cr(+6); 2CrO42−+2H+⇌Cr2O72−+H2O2\mathrm{CrO_4^{2-}}+2\mathrm{H^+}\rightleftharpoons\mathrm{Cr_2O_7^{2-}}+\mathrm{H_2O} involves no change in oxidation state, so (C) is wrong. Mn in MnO42−\mathrm{MnO_4^{2-}} is +6+6, d1d^1, so it has one unpaired electron and is paramagnetic (μ≈1.73\mu\approx1.73 BM); (D) is wrong. By contrast permanganate, Mn(+7) d0d^0, is diamagnetic, which is the likely source of the confusion. Only (B) is correct.
Report a mistake

Original question written in the JEE Advanced 2019 Paper 2 pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake