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JEE Advanced 2023 Paper 1 · Chemistry · d- and f-Block Elements and Metallurgy · easy

Match the metal in List-I with the key step of its extraction in List-II. List-I: (P) silver from argentite ore, Ag2S; (Q) copper from copper…

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Match the metal in List-I with the key step of its extraction in List-II.

List-I: (P) silver from argentite ore, Ag2S\mathrm{Ag_2S}; (Q) copper from copper pyrites, CuFeS2\mathrm{CuFeS_2}; (R) aluminium from alumina; (S) titanium from rutile, TiO2\mathrm{TiO_2} (after conversion to the tetrachloride)

List-II: (1) electrolysis of the oxide dissolved in molten cryolite; (2) auto-reduction of Cu2S\mathrm{Cu_2S} with Cu2O\mathrm{Cu_2O} in the Bessemer converter; (3) reduction with molten magnesium in an inert atmosphere; (4) displacement of the metal from its cyanide complex by zinc; (5) reduction with carbon in a blast furnace
  1. A. P→4, Q→2, R→1, S→3
  2. B. P→4, Q→5, R→1, S→3
  3. C. P→2, Q→4, R→1, S→3
  4. D. P→4, Q→2, R→3, S→1
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Answer: (A) P→4, Q→2, R→1, S→3

(P) Silver sulphide is leached with dilute aqueous NaCN\mathrm{NaCN} in air: Ag2S+4CN−→2[Ag(CN)2]−+S2−\mathrm{Ag_2S+4CN^-\to2[Ag(CN)_2]^-+S^{2-}}; the complex is then treated with zinc: Zn+2[Ag(CN)2]−→[Zn(CN)4]2−+2Ag\mathrm{Zn+2[Ag(CN)_2]^-\to[Zn(CN)_4]^{2-}+2Ag} ⇒\Rightarrow 4.
(Q) Roasted copper matte contains Cu2S\mathrm{Cu_2S} and Cu2O\mathrm{Cu_2O}, which react by self (auto) reduction in the Bessemer converter: 2Cu2O+Cu2S→6Cu+SO2\mathrm{2Cu_2O+Cu_2S\to6Cu+SO_2} ⇒\Rightarrow 2.
(R) Pure alumina dissolved in molten cryolite (Na3AlF6\mathrm{Na_3AlF_6}) with CaF2\mathrm{CaF_2} is electrolysed in the Hall-Heroult process ⇒\Rightarrow 1.
(S) Titanium is obtained by the Kroll process, TiCl4+2Mg→Ti+2MgCl2\mathrm{TiCl_4+2Mg\to Ti+2MgCl_2}, under inert argon since Ti\mathrm{Ti} forms nitride and oxide with air and carbon reduction gives carbide ⇒\Rightarrow 3.
(5) is a distractor; none of the four metals is obtained by simple carbon reduction in a blast furnace (that is used for iron). Correct code: P→4, Q→2, R→1, S→3.
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