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JEE Advanced 2019 Paper 1 · Physics · Fluid Mechanics, Elasticity and Surface Tension · medium

A wide open tank stands on a horizontal table. It contains water to a depth H=1.0 m and is kept full by a feed from above so that the level stays…

One or more options correct

A wide open tank stands on a horizontal table. It contains water to a depth H=1.0 mH=1.0\ \mathrm{m} and is kept full by a feed from above so that the level stays constant. Small holes (area much smaller than the tank cross-section) can be opened in the vertical side wall at various depths hh below the free surface. Take g=10 m s−2g=10\ \mathrm{m\,s^{-2}} and ignore viscosity. The tank rests on the table surface and the bottom of the tank is at the table level. Which of the following statements is/are correct?
  1. A. The water level in the tank must fall at a speed equal to the efflux speed of the jet from any hole.
  2. B. A jet from a hole at depth 0.20 m0.20\ \mathrm{m} strikes the table at a horizontal distance 0.80 m0.80\ \mathrm{m} from the wall.
  3. C. Holes at depths 0.20 m0.20\ \mathrm{m} and 0.80 m0.80\ \mathrm{m} give jets with the same horizontal range on the table.
  4. D. The maximum possible range of a jet on the table is 1.2 m1.2\ \mathrm{m}.
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Answer: B, C

Efflux speed at depth hh is v=2ghv=\sqrt{2gh} (Torricelli). The hole is at height H−hH-h above the table, so the fall time is t=2(H−h)/gt=\sqrt{2(H-h)/g} and the range is x=vt=2h(H−h)x=vt=2\sqrt{h(H-h)}. (A) is false: the level stays constant here, and even if it were not, the surface speed would be v a/Av\,a/A, far smaller than vv. (B) For h=0.2h=0.2: x=20.2×0.8=0.80 mx=2\sqrt{0.2\times0.8}=0.80\ \mathrm{m}, so it is true. (C) h(H−h)h(H-h) is symmetric under h→H−hh\to H-h, so h=0.2h=0.2 and 0.80.8 give the same range; true. (D) h(H−h)h(H-h) is maximum at h=H/2h=H/2, giving xmax=H=1.0 mx_{max}=H=1.0\ \mathrm{m}, not 1.2 m1.2\ \mathrm{m}; false. Correct options: (B) and (C).
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