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JEE Advanced 2020 Paper 1 · Physics · Calorimetry and Heat Transfer · medium

Two uniform rods A and B of the same length L and cross-section S are joined end to end. The thermal conductivity of A is 3k and that of B is k. The…

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Two uniform rods AA and BB of the same length LL and cross-section SS are joined end to end. The thermal conductivity of AA is 3k3k and that of BB is kk. The free end of AA is kept at 100∘C100^\circ\mathrm{C} and the free end of BB at 0∘C0^\circ\mathrm{C}. The lateral surfaces are insulated and the steady state is reached. Which of the following statements is/are correct?
  1. A. The temperature of the junction is 75∘C75^\circ\mathrm{C}.
  2. B. The rate of heat flow along the rods is 75 kS/L75\,kS/L (in units where temperature is in ∘C^\circ\mathrm{C}).
  3. C. If the same two rods were instead connected in parallel between the same temperatures, the rate of heat flow would be 83\dfrac83 times that in the series arrangement.
  4. D. If the rods are interchanged (B at 100∘C100^\circ\mathrm{C} and A at 0∘C0^\circ\mathrm{C}), the junction temperature becomes 25∘C25^\circ\mathrm{C}.
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Answer: A, B, D

In series the heat current is the same in both rods: 3kS(100−T)L=kS(T−0)L\frac{3kS(100-T)}{L}=\frac{kS(T-0)}{L}, giving T=75∘CT=75^\circ\mathrm{C}, so (A) is true. The heat current is then kS⋅75L=75 kS/L\frac{kS\cdot75}{L}=75\,kS/L, so (B) is true. In parallel, each rod spans the full 100∘C100^\circ\mathrm{C} difference, so H=(3k+k)S⋅100L=400 kS/LH=\frac{(3k+k)S\cdot100}{L}=400\,kS/L, and the ratio to the series value is 40075=163\frac{400}{75}=\frac{16}{3}, not 83\frac83, so (C) is false. When interchanged, kS(100−T)L=3kS TL\frac{kS(100-T)}{L}=\frac{3kS\,T}{L}, giving T=25∘CT=25^\circ\mathrm{C}, so (D) is true. A rod of higher conductivity has the smaller temperature drop across it. The reasoning is the thermal analogue of resistors: the conductance kS/LkS/L of each rod plays the role of 1/R1/R, with series conductances combining as reciprocals and parallel conductances adding directly.
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Original question written in the JEE Advanced 2020 Paper 1 pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake