Aromatic substitution and its limitations are used in the following statements.

(A) With $\mathrm{AlCl_3}$ the incipient primary cation $\mathrm{CH_3CH_2CH_2^+}$ undergoes a 1,2-hydride shift to the more stable secondary cation, which alkylates benzene, so isopropylbenzene (cumene) predominates: correct. (B) A nitro group strongly deactivates the ring (and complexes with $\mathrm{AlCl_3}$), so nitrobenzene does not undergo Friedel-Crafts reactions at all: wrong. (C) The acylium ion $\mathrm{CH_3CH_2CO^+}$ does not rearrange; it gives propiophenone, $\mathrm{PhCOCH_2CH_3}$. Clemmensen reduction ($\mathrm{Zn(Hg)/HCl}$) converts $\mathrm{C=O}$ to $\mathrm{CH_2}$, giving $n$-propylbenzene with no isopropyl isomer: correct. (D) Chlorine withdraws electrons by the $-I$ effect, which deactivates the ring, but its lone pairs donate by $+M$, which directs the incoming nitronium ion ortho and para. The major products are $1$-chloro-$4$-nitro and $1$-chloro-$2$-nitrobenzene: wrong.