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JEE Advanced 2016 Paper 1 · Chemistry · Hydrocarbons · medium

Transformations of aromatic compounds give the stated major product?

One or more options correct

Which of the following transformations of aromatic compounds give the stated major product?
  1. A. Benzene →CH3COCl, anhyd. AlCl3 →Zn(Hg), conc. HCl\xrightarrow{\mathrm{CH_3COCl,\ anhyd.\ AlCl_3}}\ \xrightarrow{\mathrm{Zn(Hg),\ conc.\ HCl}} ethylbenzene
  2. B. Nitrobenzene →CH3Cl, anhyd. AlCl3\xrightarrow{\mathrm{CH_3Cl,\ anhyd.\ AlCl_3}} mm-nitrotoluene
  3. C. Aniline →conc. HNO3/conc. H2SO4\xrightarrow{\mathrm{conc.\ HNO_3/conc.\ H_2SO_4}} exclusively pp-nitroaniline
  4. D. Phenol →CHCl3, aq. NaOH →H3O+\xrightarrow{\mathrm{CHCl_3,\ aq.\ NaOH}}\ \xrightarrow{\mathrm{H_3O^+}} pp-hydroxybenzaldehyde as the major product
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Answer: A

(A) Correct. Friedel-Crafts acylation gives acetophenone, which the Clemmensen reduction converts to ethylbenzene; acylation is used because direct alkylation with ethyl halide could rearrange or poly-alkylate. (B) Incorrect. The strongly deactivating −NO2\mathrm{-NO_2} group makes nitrobenzene unreactive in Friedel-Crafts alkylation, and the AlCl3\mathrm{AlCl_3} also complexes with it. (C) Incorrect. In strongly acidic medium aniline is protonated to the anilinium ion, a meta director, so a large amount of mm-nitroaniline is formed together with oxidation products; the product is not exclusively para. (D) Incorrect. In the Reimer-Tiemann reaction the electrophilic dichlorocarbene attacks the ortho position of the phenoxide, so salicylaldehyde is the major product and the para isomer is minor.
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