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JEE Advanced 2022 Paper 1 · Chemistry · s-Block, p-Block Elements and Hydrogen · hard

(s) about s-block compounds.

One or more options correct

Choose the correct statement(s) about s-block compounds.
  1. A. On strong heating, LiNO3\mathrm{LiNO_3} gives Li2O\mathrm{Li_2O}, NO2\mathrm{NO_2} and O2\mathrm{O_2}, whereas NaNO3\mathrm{NaNO_3} gives NaNO2\mathrm{NaNO_2} and O2\mathrm{O_2}
  2. B. Potassium superoxide KO2\mathrm{KO_2} is diamagnetic, since the superoxide ion has all its electrons paired
  3. C. Solid BeCl2\mathrm{BeCl_2} is a chain polymer in which each Be atom is sp2sp^2-hybridised and trigonal planar
  4. D. Sodium peroxide Na2O2\mathrm{Na_2O_2} is paramagnetic because of the unpaired electrons in the peroxide ion
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Answer: A

A is correct: the small, strongly polarising Li+\mathrm{Li^+} stabilises the oxide and the nitrate decomposes as 4LiNO3→2Li2O+4NO2+O2\mathrm{4LiNO_3\to2Li_2O+4NO_2+O_2}, while the sodium and potassium nitrates stop at the nitrite. B is incorrect: the superoxide ion O2−\mathrm{O_2^-} has 1313 valence electrons, three of them in the π∗\pi^* level, so one electron is unpaired; it is paramagnetic with bond order 1.51.5. C is incorrect: in the chain of solid BeCl2\mathrm{BeCl_2} each Be is bonded to four bridging chlorine atoms (3c-4e type bonding), tetrahedral and sp3sp^3 hybridised; the planar sp2sp^2 picture applies to the gas-phase monomer. D is incorrect: the peroxide ion O22−\mathrm{O_2^{2-}} has bond order 11 and all electrons paired in π∗\pi^*, so it is diamagnetic. Only A is correct.
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