PrepRung
Sign inSign up free

Home / JEE Main / 2017

JEE Main 2017 · April (offline)

A full paper in the 2017 pattern: Physics, Chemistry and Mathematics, 30 MCQs each, one 180-minute clock. Take it as a timed mock or open it in learn mode and check every answer.

90questions
180 minone clock
360maximum marks
16/52/22easy / medium / hard
Start timed mockStudy with solutions

Marking scheme and topics

+4 for a correct answer, −1 for a wrong answer. Each subject has 30 questions.

Physics · 30 questions

  • Units and measurements1
  • Kinematics1
  • Work, energy and springs1
  • Momentum and energy1
  • Rotational equilibrium1
  • Compound pendulum1
  • Gravitation1
  • Fluid flow (Torricelli)1
  • Heat conduction1
  • Calorimetry1
  • Thermodynamic cycles1
  • Thermodynamic processes1
  • Thermodynamics of mixing1
  • Simple harmonic motion1

Chemistry · 30 questions

  • Mole concept and stoichiometry1
  • Chemical thermodynamics1
  • Chemical equilibrium (heterogeneous)1
  • Ionic equilibrium (buffers)1
  • Chemical kinetics1
  • Electrochemistry (electrolysis)1
  • Solutions (colligative properties)1
  • Atomic structure (Bohr model, photoelectric effect)1
  • Thermochemistry (calorimetry)1
  • Solid state1
  • Periodic properties1
  • Chemical bonding (bond angles)1
  • Chemical bonding (MOT)1
  • Coordination compounds (CFT)1

Mathematics · 30 questions

  • Complex numbers2
  • Sequences and series2
  • Permutations and combinations2
  • Matrices and determinants2
  • Application of derivatives2
  • Three dimensional geometry2
  • Sets1
  • Relations1
  • Quadratic equations1
  • Binomial theorem1
  • Limits1
  • Continuity1
  • Differentiation1
  • Definite integrals1

Sample question from this paper

Physics · Kinematics · medium

A stone is projected vertically upward with speed 20 m s−120\ \mathrm{m\,s^{-1}} from the top of a tower 25 m25\ \mathrm{m} high. Taking g=10 m s−2g = 10\ \mathrm{m\,s^{-2}} and neglecting air resistance, the average speed of the stone from projection until it strikes the ground is
  1. A. 5 m s−15\ \mathrm{m\,s^{-1}}
  2. B. 9 m s−19\ \mathrm{m\,s^{-1}}
  3. C. 13 m s−113\ \mathrm{m\,s^{-1}}
  4. D. 15 m s−115\ \mathrm{m\,s^{-1}}
Show answer and solution
Answer: C
Taking up as positive and the ground as −25 m-25\ \mathrm{m}: −25=20t−5t2-25 = 20t - 5t^2, so t2−4t−5=0t^2 - 4t - 5 = 0 and t=5 st = 5\ \mathrm{s}. The stone rises h=202/(2×10)=20 mh = 20^2/(2\times 10) = 20\ \mathrm{m} and then falls 20+25=45 m20 + 25 = 45\ \mathrm{m}, so the total path length is 65 m65\ \mathrm{m}. Average speed =65/5=13 m s−1= 65/5 = 13\ \mathrm{m\,s^{-1}}. The value 5 m s−15\ \mathrm{m\,s^{-1}} is the magnitude of the average velocity (25/525/5), which is a different quantity because displacement is not path length.

Other years

JEE Main 2025JEE Main 2024JEE Main 2023JEE Main 2022JEE Main 2021JEE Main 2020JEE Main 2019JEE Main 2018JEE Main 2016JEE Main pattern and all papers