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JEE Main 2020 · January session

A full paper in the 2020 pattern: Physics, Chemistry and Mathematics, 20 MCQs + 5 numerical each, one 180-minute clock. Take it as a timed mock or open it in learn mode and check every answer.

75questions

180 minone clock

300maximum marks

14/44/17easy / medium / hard

Start timed mock Study with solutions

Marking scheme and topics

+4 for a correct answer, −1 for a wrong MCQ, no negative marking on numericals. Each subject has 25 questions: Section A multiple choice, Section B numerical value.

Physics · 25 questions

Current electricity2
Units and measurements1
Kinematics1
Laws of motion and friction1
Circular motion and work-energy1
Rotational motion1
Gravitation1
Thermodynamics1
Calorimetry1
Sound waves1
Doppler effect1
Capacitors and dielectrics1
Gauss's law1
Magnetic effect of current1

Chemistry · 25 questions

Electrochemistry2
Chemical bonding2
Hydrocarbons2
Mole concept1
Chemical equilibrium1
Chemical thermodynamics1
Chemical kinetics1
Solutions and colligative properties1
Atomic structure1
Redox titrations1
Coordination compounds1
p-block elements1
Metallurgy1
s-block elements1

Mathematics · 25 questions

Quadratic equations2
Sequences and series2
Definite integrals2
Three-dimensional geometry2
Sets1
Complex numbers1
Permutations and combinations1
Binomial theorem1
Matrices and determinants1
Determinants and linear systems1
Limits1
Continuity1
Differentiation1
Applications of derivatives1

Sample question from this paper

Physics · Units and measurements · medium

In an experiment on the simple pendulum, the length is measured as

L = 100.0\ \mathrm{cm}

with a metre scale of least count

0.1\ \mathrm{cm}

, and the total time for

20

oscillations is measured as

40.0\ \mathrm{s}

with a stopwatch of least count

0.2\ \mathrm{s}

. The maximum percentage error in the value of

g

obtained from

T = 2\pi\sqrt{L/g}

A. $0.6\%$
B. $1.1\%$
C. $1.6\%$
D. $2.1\%$

Show answer and solution

Answer: B

g = 4\pi^2 L/T^2

with

T = t/20

, so

\frac{\Delta g}{g} = \frac{\Delta L}{L} + 2\frac{\Delta t}{t}

(the factor 20 is exact).

\frac{\Delta L}{L} = \frac{0.1}{100.0} = 0.1\%

and

\frac{\Delta t}{t} = \frac{0.2}{40.0} = 0.5\%

. Hence

\frac{\Delta g}{g} = 0.1 + 2(0.5) = 1.1\%

. Common slip: forgetting that

T

enters squared gives

0.6\%

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