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JEE Main 2018 · April (offline)

A full paper in the 2018 pattern: Physics, Chemistry and Mathematics, 30 MCQs each, one 180-minute clock. Take it as a timed mock or open it in learn mode and check every answer.

90questions
180 minone clock
360maximum marks
21/50/19easy / medium / hard

Marking scheme and topics

+4 for a correct answer, −1 for a wrong answer. Each subject has 30 questions.

Physics · 30 questions

  • Units and measurement1
  • Relative motion1
  • Projectile motion1
  • Laws of motion1
  • Work, energy and power1
  • Circular motion1
  • Rotational motion1
  • Gravitation1
  • Optical instruments1
  • Fluid mechanics1
  • Thermodynamics1
  • Carnot cycle and refrigerators1
  • Kinetic theory of gases1
  • Simple harmonic motion1

Chemistry · 30 questions

  • Mole concept / stoichiometry1
  • Chemical equilibrium1
  • Thermochemistry1
  • Chemical kinetics1
  • Electrochemistry1
  • Colligative properties / association1
  • Atomic structure1
  • Ionic equilibrium / buffers1
  • Electrochemistry / conductance1
  • Solid state1
  • General organic chemistry / alkenes1
  • Hydrocarbons / carbonyl chemistry1
  • Haloalkanes / substitution1
  • Alcohols / qualitative analysis1

Mathematics · 30 questions

  • Matrices and determinants3
  • Complex numbers2
  • Sequences and series2
  • Permutations and combinations2
  • Binomial theorem2
  • Applications of derivatives2
  • Integration2
  • Sets1
  • Relations1
  • Quadratic equations1
  • Limits1
  • Continuity1
  • Differentiation1
  • Area under curves1

Sample question from this paper

Physics · Units and measurement · medium

To find gg, a student times 2020 oscillations of a simple pendulum. The length is measured as 1.00 m1.00\ \mathrm{m} with a metre rule of least count 1 cm1\ \mathrm{cm}, and the total time for 2020 oscillations is 40.0 s40.0\ \mathrm{s} with a stopwatch of least count 0.1 s0.1\ \mathrm{s}. The maximum percentage error in the value of gg is
  1. A. 2.0%2.0\%
  2. B. 2.25%2.25\%
  3. C. 1.25%1.25\%
  4. D. 1.5%1.5\%
Show answer and solution
Answer: D
From T=2πL/gT=2\pi\sqrt{L/g} we get g=4π2L/T2g=4\pi^2L/T^2, so Δgg=ΔLL+2ΔTT\dfrac{\Delta g}{g}=\dfrac{\Delta L}{L}+2\dfrac{\Delta T}{T}. The length error is 1 cm100 cm=1%\dfrac{1\ \mathrm{cm}}{100\ \mathrm{cm}}=1\%. The period is found from the total time tt of 2020 oscillations, so ΔTT=Δtt=0.140.0=0.25%\dfrac{\Delta T}{T}=\dfrac{\Delta t}{t}=\dfrac{0.1}{40.0}=0.25\% (the count 2020 is exact and does not change the fractional error). Hence Δgg=1%+2(0.25%)=1.5%\dfrac{\Delta g}{g}=1\%+2(0.25\%)=1.5\%. A common slip is to omit the square on TT, which gives 1.25%1.25\%.