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JEE Main 2021 · February session

A full paper in the 2021 pattern: Physics, Chemistry and Mathematics, 20 MCQs + 10 numerical (answer any 5) each, one 180-minute clock. Take it as a timed mock or open it in learn mode and check every answer.

90questions, 75 counted
180 minone clock
300maximum marks
16/56/18easy / medium / hard
Start timed mockStudy with solutions

Marking scheme and topics

+4 for a correct answer, −1 for a wrong MCQ or numerical answer. Each subject has 30 questions: Section A multiple choice, Section B numerical value.

Physics · 30 questions

  • Rotational motion2
  • Units and errors1
  • Laws of motion and friction1
  • Gravitation1
  • Thermodynamics1
  • Heat transfer1
  • Waves and Doppler effect1
  • Capacitance and dielectrics1
  • Current electricity (potentiometer)1
  • Motion of charges in magnetic field1
  • Electromagnetic induction (LR circuit)1
  • Alternating current1
  • Wave optics (YDSE)1
  • Ray optics1

Chemistry · 30 questions

  • Atomic structure2
  • Chemical kinetics2
  • Electrochemistry2
  • Coordination compounds2
  • Mole concept1
  • Chemical thermodynamics1
  • Chemical equilibrium1
  • Solutions1
  • Ionic equilibrium1
  • Amines / GOC1
  • Hydrocarbons1
  • Haloalkanes / stereochemistry1
  • Amines / named reactions1
  • Biomolecules1

Mathematics · 30 questions

  • Complex numbers2
  • Sequences and series2
  • Permutations and combinations2
  • Binomial theorem2
  • Matrices2
  • Definite integrals2
  • Three-dimensional geometry2
  • Probability2
  • Sets and relations1
  • Quadratic equations1
  • Determinants1
  • Limits1
  • Continuity and differentiability1
  • Differentiation1

Sample question from this paper

Physics · Laws of motion and friction · medium

A block is released from rest at the top of a rough incline of angle 37∘37^\circ (sin⁡37∘=0.6\sin37^\circ=0.6) and slides 5 m5\ \mathrm{m} along it; the coefficient of kinetic friction on the incline is 0.250.25. At the bottom it moves smoothly onto a horizontal surface where the coefficient of kinetic friction is 0.50.5. Taking g=10 m s−2g=10\ \mathrm{m\,s^{-2}}, the distance it travels on the horizontal surface before stopping is
  1. A. 2 m2\ \mathrm{m}
  2. B. 5 m5\ \mathrm{m}
  3. C. 4 m4\ \mathrm{m}
  4. D. 8 m8\ \mathrm{m}
Show answer and solution
Answer: C
On the incline a=g(sin⁡θ−μcos⁡θ)=10(0.6−0.25×0.8)=4 m s−2a=g(\sin\theta-\mu\cos\theta)=10(0.6-0.25\times0.8)=4\ \mathrm{m\,s^{-2}}, so v2=2aL=2(4)(5)=40 m2s−2v^2=2aL=2(4)(5)=40\ \mathrm{m^2s^{-2}}. On the horizontal surface the deceleration is μg=5 m s−2\mu g=5\ \mathrm{m\,s^{-2}}, so d=v2/(2μg)=40/10=4 md=v^2/(2\mu g)=40/10=4\ \mathrm{m}. (Work-energy shortcut: mg h−μ1mgcos⁡θ L=μ2mg dmg\,h-\mu_1 mg\cos\theta\,L=\mu_2 mg\,d.)

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