Single correct option
2-Bromo-2,3-dimethylpentane, , is heated separately with (i) sodium ethoxide in ethanol and (ii) potassium tert-butoxide in tert-butanol. The major alkenes (i), (ii) respectively are
- A. 2,3-dimethylpent-1-ene; 2,3-dimethylpent-2-ene
- B. 2,3-dimethylpent-2-ene; 2,3-dimethylpent-2-ene
- C. 2,3-dimethylpent-2-ene; 2,3-dimethylpent-1-ene
- D. 2,3-dimethylpent-1-ene; 2,3-dimethylpent-1-ene
Show answer and solution
Answer: (C) 2,3-dimethylpent-2-ene; 2,3-dimethylpent-1-ene
The -hydrogens are on the two methyl groups at C-2 (giving the terminal alkene, 2,3-dimethylpent-1-ene) and on C-3 (giving the tetrasubstituted 2,3-dimethylpent-2-ene). The small base ethoxide gives the more substituted, more stable Zaitsev product. The bulky tert-butoxide cannot easily reach the crowded tertiary C-3 hydrogen and removes a less hindered methyl hydrogen instead, so the Hofmann product dominates.
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