JEE Main 2022 · Chemistry · Alcohols, Phenols, Ethers and Haloalkanes · medium

In the cumene process, 240 g of cumene (C9H12, M=120) is converted to phenol (M=94) and acetone (M=58) with an overall yield of 75% of each product.…

Numerical answer

In the cumene process,

240\ \mathrm g

of cumene (

\mathrm{C_9H_{12}}

M=120

) is converted to phenol (

M=94

) and acetone (

M=58

) with an overall yield of

75\%

of each product. The combined mass of phenol and acetone obtained, in grams, is

Show answer and solution

Answer: 228

Cumene is oxidised by air to cumene hydroperoxide, which is cleaved by dilute acid to phenol and acetone in

1:1

mole ratio. Moles of cumene

=240/120=2.0

. At

75\%

yield,

1.5

mol of each product forms. Phenol

=1.5\times94=141

g and acetone

=1.5\times58=87

g. Total

=141+87=228

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