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JEE Main 2019 · Chemistry · Coordination Compounds · easy

The total number of stereoisomers possible for the two complex ions [Co(en)2Cl2]^+ and [Co(en)3]^3+ taken together is (en = ethane-1,2-diamine)

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The total number of stereoisomers possible for the two complex ions [Co(en)2Cl2]+[\mathrm{Co(en)_2Cl_2}]^+ and [Co(en)3]3+[\mathrm{Co(en)_3}]^{3+} taken together is (en = ethane-1,2-diamine)
  1. A. 3
  2. B. 5
  3. C. 4
  4. D. 6
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Answer: (B) 5

[Co(en)2Cl2]+[\mathrm{Co(en)_2Cl_2}]^+ is octahedral M(AA)2b2M(AA)_2b_2: the trans form is achiral (one isomer, has a mirror plane); the cis form lacks a mirror plane and exists as a pair of enantiomers. That gives 3 stereoisomers. [Co(en)3]3+[\mathrm{Co(en)_3}]^{3+} has three chelate rings arranged like a propeller, giving Δ\Delta and Λ\Lambda enantiomers: 2. Total =3+2=5=3+2=5.
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Original question written in the JEE Main 2019 pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake