PrepRung

JEE Main 2024 · Physics · Kinematics and Laws of Motion · hard

A block A of mass 2 kg lies on a smooth horizontal table. A light string tied to A passes over a smooth fixed pulley at the table edge, then goes…

Single correct option

A block AA of mass 2 kg2\ \mathrm{kg} lies on a smooth horizontal table. A light string tied to AA passes over a smooth fixed pulley at the table edge, then goes down and around a light movable pulley that carries a block BB of mass 4 kg4\ \mathrm{kg}, and its other end is fixed to the ceiling (both hanging parts of the string are vertical). The tension in the string after the system is released is (g=10 m s−2g=10\ \mathrm{m\,s^{-2}})
  1. A. 20.0 N20.0\ \mathrm{N}
  2. B. 16.0 N16.0\ \mathrm{N}
  3. C. 10.0 N10.0\ \mathrm{N}
  4. D. 13.3 N13.3\ \mathrm{N}
Show answer and solution

Answer: (D) 13.3 N13.3\ \mathrm{N}

The movable pulley hangs on two string segments, so if BB descends with acceleration aBa_B, the string end at AA moves with aA=2aBa_A=2a_B (constraint). For AA: T=2aAT=2a_A. For BB (two segments pull up): 4g−2T=4aB=2aA4g-2T=4a_B=2a_A. Substituting T=2aAT=2a_A: 40−4aA=2aA40-4a_A=2a_A, so aA=203 m s−2a_A=\dfrac{20}{3}\ \mathrm{m\,s^{-2}} and T=403≈13.3 NT=\dfrac{40}{3}\approx13.3\ \mathrm{N}. Ignoring the factor 2 in the constraint gives a wrong tension.
Report a mistake

Original question written in the JEE Main 2024 pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake