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JEE Main 2025 · Mathematics · Statistics · medium

If three of them are 3,5,7 and the other two are x and y, then |x-y| equals

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Five observations have mean 77 and variance 88. If three of them are 3,5,73,5,7 and the other two are xx and yy, then ∣x−y∣|x-y| equals
  1. A. 11
  2. B. 22
  3. C. 33
  4. D. 44
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Answer: (B) 22

Sum =35=35, so x+y=35−15=20x+y=35-15=20. From σ2=∑xi25−xˉ2\sigma^2=\frac{\sum x_i^2}{5}-\bar{x}^2 we get ∑xi2=5(8+49)=285\sum x_i^2=5(8+49)=285. The known squares total 9+25+49=839+25+49=83, so x2+y2=202x^2+y^2=202. Then 2xy=400−202=1982xy=400-202=198, xy=99xy=99, and (x−y)2=(x+y)2−4xy=400−396=4(x-y)^2=(x+y)^2-4xy=400-396=4. So ∣x−y∣=2|x-y|=2 (indeed x,y=9,11x,y=9,11).
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