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JEE Main 2024 · Mathematics · Straight Lines and Circles · easy

The lines 2x+3y=5 and kx-6y=7 are perpendicular. The value of k is

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The lines 2x+3y=52x+3y=5 and kx−6y=7kx-6y=7 are perpendicular. The value of kk is
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Answer: 9

Two lines a1x+b1y=c1a_1x+b_1y=c_1 and a2x+b2y=c2a_2x+b_2y=c_2 are perpendicular when a1a2+b1b2=0a_1a_2+b_1b_2=0. So 2k+3(−6)=02k+3(-6)=0, giving k=9k=9. (Slopes: −23-\tfrac23 and k6=32\tfrac{k}{6}=\tfrac32, product −1-1.)
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