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NDA 2019 Maths · Mathematics · Application of Derivatives · hard

The function f(x)=x^3 is strictly increasing on mathbb R even though f'(0)=0. 2. The function f(x)=1/x is decreasing on its entire domain mathbb…

Single correct option

Consider the following statements:
1. The function f(x)=x3f(x)=x^3 is strictly increasing on R\mathbb R even though f′(0)=0f'(0)=0.
2. The function f(x)=1xf(x)=\frac1x is decreasing on its entire domain R∖{0}\mathbb R\setminus\{0\}.
Which of the statements given above is/are correct?
  1. A. 1 only
  2. B. 2 only
  3. C. Both 1 and 2
  4. D. Neither 1 nor 2
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Answer: (A) 1 only

Statement 1: f′(x)=3x2≥0f'(x)=3x^2\ge0 and vanishes only at the single point 00, so ff is strictly increasing; true. Statement 2: ff decreases on (−∞,0)(-\infty,0) and on (0,∞)(0,\infty) separately, but f(−1)=−1<f(1)=1f(-1)=-1<f(1)=1 with −1<1-1<1, so it is not decreasing on the whole domain; false. Only statement 1 is correct.
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Original question written in the NDA 2019 Maths pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake