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NDA 2025 Maths · Mathematics · Matrices · hard

Let A be a 2×2 real matrix with A^2=I and A≠± I. Then tr(A) equals

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Let AA be a 2×22\times2 real matrix with A2=IA^2=I and A≠±IA\ne\pm I. Then tr⁡(A)\operatorname{tr}(A) equals
  1. A. 00
  2. B. 11
  3. C. 22
  4. D. −2-2
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Answer: (A) 00

A2=IA^2=I gives (A−I)(A+I)=O(A-I)(A+I)=O. As A≠±IA\ne\pm I, neither factor is zero, so the eigenvalues are 11 and −1-1 (both occur). The trace is their sum, 00. Example: A=diag⁡(1,−1)A=\operatorname{diag}(1,-1).
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