The slope of the line 2x+3y=6 is 2/3. 2. The x-intercept of the line 2x+3y=6 is 2.

Writing $y=-\dfrac23x+2$ shows that the slope is $-\dfrac23$, not $\dfrac23$, so statement 1 is false; the sign is the whole trap. Putting $y=0$ gives $2x=6$, so the x-intercept is $3$, and $2$ is the y-intercept (put $x=0$: $3y=6$). Statement 2 is therefore false as well, since it confuses the two intercepts. Neither statement is correct.