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CAT 2020 Slot 2 · DILR · Data Interpretation · medium

CAT 2020 Slot 2 DILR: Marks in Four Tests

Five students — Aditi, Bharat, Charu, Dev and Esha — took four tests (T1 to T4), each marked out of 50. All scores are whole numbers. The table shows some of the scores; a '?' marks a score that has been smudged out.

| Student | T1 | T2 | T3 | T4 | Average (4 tests) |
|---|---|---|---|---|---|
| Aditi | ? | 38 | ? | 35 | 40 |
| Bharat | 30 | ? | ? | 42 | 38 |
| Charu | 48 | ? | 32 | ? | 39 |
| Dev | 25 | 35 | 40 | ? | 36 |
| Esha | ? | 33 | 47 | 28 | ? |
| Class average | 37 | 38 | 40 | 37 | |

The class average for a test is the average of the five students' scores in that test.

Question 1

Numerical answer

What was Aditi's score in T1?
Show answer and solution

Answer: 42

Totals: row totals = 4 × average (Aditi 160, Bharat 152, Charu 156, Dev 144); column totals = 5 × class average (T1 185, T2 190, T3 200, T4 185).

Peel off one unknown at a time:

1. Dev T4 = 144 − 100 = 44
2. Charu T4 = 185 − (35 + 42 + 44 + 28) = 36
3. Charu T2 = 156 − (48 + 32 + 36) = 40
4. Bharat T2 = 190 − (38 + 40 + 35 + 33) = 44
5. Bharat T3 = 152 − (30 + 44 + 42) = 36
6. Aditi T3 = 200 − (36 + 32 + 40 + 47) = 45
7. Aditi T1 = 160 − (38 + 45 + 35) = 42
8. Esha T1 = 185 − (42 + 30 + 48 + 25) = 40

| Student | T1 | T2 | T3 | T4 | Total |
|---|---|---|---|---|---|
| Aditi | 42 | 38 | 45 | 35 | 160 |
| Bharat | 30 | 44 | 36 | 42 | 152 |
| Charu | 48 | 40 | 32 | 36 | 156 |
| Dev | 25 | 35 | 40 | 44 | 144 |
| Esha | 40 | 33 | 47 | 28 | 148 |

Aditi's T1 score = 42.

Tip: start from a row or column that has only one '?' (Dev's row), then keep going through rows and columns in turn.

Question 2

Single correct option

What was Esha's average score across the four tests?
  1. A. 36
  2. B. 37
  3. C. 37.5
  4. D. 38
Show answer and solution

Answer: (B) 37

Esha's average is not given, but the grand total can be computed from the class averages: 5 × (37 + 38 + 40 + 37) = 760.

The other four students' totals are 160 + 152 + 156 + 144 = 612, so Esha's total = 760 − 612 = 148 and her average = 37.

Check with the completed grid: 40 + 33 + 47 + 28 = 148. ✓

Question 3

Single correct option

How many students scored more than 40 in at least two of the four tests?
  1. A. 1
  2. B. 2
  3. C. 3
  4. D. 4
Show answer and solution

Answer: (B) 2

Completed grid:

- Aditi 42, 38, 45, 35: two scores above 40 ✓
- Bharat 30, 44, 36, 42: two ✓
- Charu 48, 40, 32, 36: one (40 is not *more than* 40)
- Dev 25, 35, 40, 44: one
- Esha 40, 33, 47, 28: one

Answer: 2.

Trap: counting a score of exactly 40 gives 4.

Question 4

Single correct option

For the final ranking, each student's lowest test score is dropped and the other three are added. Who ranks second?
  1. A. Aditi
  2. B. Bharat
  3. C. Charu
  4. D. Esha
Show answer and solution

Answer: (C) Charu

Best-three totals (total − lowest score):

- Aditi 160 − 35 = 125
- Bharat 152 − 30 = 122
- Charu 156 − 32 = 124
- Dev 144 − 25 = 119
- Esha 148 − 28 = 120

Order: Aditi, Charu, Bharat, Esha, Dev. Charu ranks second.

Question 5

Numerical answer

What is the difference between the highest and the lowest score in T2?
Show answer and solution

Answer: 11

T2 scores: Aditi 38, Bharat 44, Charu 40, Dev 35, Esha 33 (Bharat's and Charu's were deduced; see the completed grid).

Highest − lowest = 44 − 33 = 11.
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Original question written in the CAT 2020 Slot 2 pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake