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CAT 2019 Slot 2 · DILR · Data Interpretation · medium

CAT 2019 Slot 2 DILR: Relay Race Timings

Four teams – Aces, Bolts, Comets and Dashers – took part in a 4 × 400 m relay race. Each team had four runners, one for each leg. The table below shows the time (in seconds) taken by each team's runner in each leg; some entries are missing and are shown as '?'.

| Team | Leg 1 | Leg 2 | Leg 3 | Leg 4 |
|---|---|---|---|---|
| Aces | 52 | ? | 50 | 47 |
| Bolts | 50 | 53 | ? | 49 |
| Comets | ? | 46 | 52 | ? |
| Dashers | 51 | ? | 51 | ? |

The standings (first to last) at the end of each leg, based on the total time taken till then, were:

| After | 1st | 2nd | 3rd | 4th |
|---|---|---|---|---|
| Leg 1 | Bolts | Dashers | Aces | Comets |
| Leg 2 | Comets | Aces | Dashers | Bolts |
| Leg 3 | Bolts | Aces | Comets | Dashers |
| Leg 4 | Aces | Bolts | Comets | Dashers |

Additional information:

- Every leg time was a whole number of seconds from 45 to 55 (both inclusive).
- No two teams were ever level at the end of any leg.
- The winning margin (between 1st and 2nd at the finish) was exactly 1 second, and the last team finished exactly 5 seconds after the winner.
- For Comets, the difference between their slowest and fastest leg times was 8 seconds.
- Dashers' first three runners recorded identical times.
- Comets' final-leg runner was faster than Bolts' final-leg runner.

Question 1

Numerical answer

What was the time (in seconds) of Aces' runner in Leg 2?
Show answer and solution

Answer: 49

Completed table (cumulative times in brackets):

| Team | Leg 1 | Leg 2 | Leg 3 | Leg 4 | Total |
|---|---|---|---|---|---|
| Aces | 52 (52) | 49 (101) | 50 (151) | 47 (198) | 198 |
| Bolts | 50 (50) | 53 (103) | 47 (150) | 49 (199) | 199 |
| Comets | 54 (54) | 46 (100) | 52 (152) | 48 (200) | 200 |
| Dashers | 51 (51) | 51 (102) | 51 (153) | 50 (203) | 203 |

Key steps: Dashers' leg 2 = 51 (identical times). Comets last after leg 1 → leg 1 > 52; first after leg 2 → leg 1 + 46 < 101 → leg 1 ≤ 54; the 8-second spread with a 46 forces leg 1 = 54. After leg 2 order C(100) < A < D(102) < B(103) gives Aces' leg 2 = 49 (A = 101). After leg 3 Bolts lead Aces (151): 103 + x < 151 → x ≤ 47. Finish: Aces win by 1 s, and the runner-up is Bolts → Bolts total = 199 = 103 + x + 49 → x = 47 (150 after leg 3). Comets are 3rd: 199 < 152 + y and y < 49 (faster than Bolts' 49) → y = 48 (200). Dashers are last, 5 s behind the winner: 203 → leg 4 = 203 − 153 = 50.

Aces must be 2nd after Leg 2, between Comets (100) and Dashers (102): 52 + x = 101 → x = 49.

Question 2

Single correct option

What was the total time taken by Dashers?
  1. A. 201 seconds
  2. B. 203 seconds
  3. C. 204 seconds
  4. D. 202 seconds
Show answer and solution

Answer: (B) 203 seconds

Completed table (cumulative times in brackets):

| Team | Leg 1 | Leg 2 | Leg 3 | Leg 4 | Total |
|---|---|---|---|---|---|
| Aces | 52 (52) | 49 (101) | 50 (151) | 47 (198) | 198 |
| Bolts | 50 (50) | 53 (103) | 47 (150) | 49 (199) | 199 |
| Comets | 54 (54) | 46 (100) | 52 (152) | 48 (200) | 200 |
| Dashers | 51 (51) | 51 (102) | 51 (153) | 50 (203) | 203 |

Key steps: Dashers' leg 2 = 51 (identical times). Comets last after leg 1 → leg 1 > 52; first after leg 2 → leg 1 + 46 < 101 → leg 1 ≤ 54; the 8-second spread with a 46 forces leg 1 = 54. After leg 2 order C(100) < A < D(102) < B(103) gives Aces' leg 2 = 49 (A = 101). After leg 3 Bolts lead Aces (151): 103 + x < 151 → x ≤ 47. Finish: Aces win by 1 s, and the runner-up is Bolts → Bolts total = 199 = 103 + x + 49 → x = 47 (150 after leg 3). Comets are 3rd: 199 < 152 + y and y < 49 (faster than Bolts' 49) → y = 48 (200). Dashers are last, 5 s behind the winner: 203 → leg 4 = 203 − 153 = 50.

Winner Aces = 198 s; the last team (Dashers) finished 5 s later → 203 s.

Question 3

Single correct option

Of the sixteen individual leg times, how many were 50 seconds or more?
  1. A. 8
  2. B. 9
  3. C. 10
  4. D. 11
Show answer and solution

Answer: (C) 10

Completed table (cumulative times in brackets):

| Team | Leg 1 | Leg 2 | Leg 3 | Leg 4 | Total |
|---|---|---|---|---|---|
| Aces | 52 (52) | 49 (101) | 50 (151) | 47 (198) | 198 |
| Bolts | 50 (50) | 53 (103) | 47 (150) | 49 (199) | 199 |
| Comets | 54 (54) | 46 (100) | 52 (152) | 48 (200) | 200 |
| Dashers | 51 (51) | 51 (102) | 51 (153) | 50 (203) | 203 |

Key steps: Dashers' leg 2 = 51 (identical times). Comets last after leg 1 → leg 1 > 52; first after leg 2 → leg 1 + 46 < 101 → leg 1 ≤ 54; the 8-second spread with a 46 forces leg 1 = 54. After leg 2 order C(100) < A < D(102) < B(103) gives Aces' leg 2 = 49 (A = 101). After leg 3 Bolts lead Aces (151): 103 + x < 151 → x ≤ 47. Finish: Aces win by 1 s, and the runner-up is Bolts → Bolts total = 199 = 103 + x + 49 → x = 47 (150 after leg 3). Comets are 3rd: 199 < 152 + y and y < 49 (faster than Bolts' 49) → y = 48 (200). Dashers are last, 5 s behind the winner: 203 → leg 4 = 203 − 153 = 50.

Count ≥ 50: Aces 52, 50 (2); Bolts 50, 53 (2); Comets 54, 52 (2); Dashers 51, 51, 51, 50 (4) → 10.

Question 4

Single correct option

What was Bolts' time in Leg 3, and by how many seconds did Comets finish ahead of Dashers?
  1. A. 47 seconds; 3 seconds
  2. B. 46 seconds; 4 seconds
  3. C. 47 seconds; 2 seconds
  4. D. 48 seconds; 3 seconds
Show answer and solution

Answer: (A) 47 seconds; 3 seconds

Completed table (cumulative times in brackets):

| Team | Leg 1 | Leg 2 | Leg 3 | Leg 4 | Total |
|---|---|---|---|---|---|
| Aces | 52 (52) | 49 (101) | 50 (151) | 47 (198) | 198 |
| Bolts | 50 (50) | 53 (103) | 47 (150) | 49 (199) | 199 |
| Comets | 54 (54) | 46 (100) | 52 (152) | 48 (200) | 200 |
| Dashers | 51 (51) | 51 (102) | 51 (153) | 50 (203) | 203 |

Key steps: Dashers' leg 2 = 51 (identical times). Comets last after leg 1 → leg 1 > 52; first after leg 2 → leg 1 + 46 < 101 → leg 1 ≤ 54; the 8-second spread with a 46 forces leg 1 = 54. After leg 2 order C(100) < A < D(102) < B(103) gives Aces' leg 2 = 49 (A = 101). After leg 3 Bolts lead Aces (151): 103 + x < 151 → x ≤ 47. Finish: Aces win by 1 s, and the runner-up is Bolts → Bolts total = 199 = 103 + x + 49 → x = 47 (150 after leg 3). Comets are 3rd: 199 < 152 + y and y < 49 (faster than Bolts' 49) → y = 48 (200). Dashers are last, 5 s behind the winner: 203 → leg 4 = 203 − 153 = 50.

Bolts lead after Leg 3 with Aces at 151, so 103 + x ≤ 150 → x ≤ 47. Bolts then finish 2nd at 1 second behind Aces (198) → 199 = 103 + x + 49 → x = 47. Comets 200 vs Dashers 203 → 3 seconds.
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Original question written in the CAT 2019 Slot 2 pattern and checked twice for the correct answer. Not an official question paper. How we write and check questions · Corrections policy · Report a mistake