Single correct option
In a group of 100 students, 60 drink tea, 50 drink coffee and 40 drink juice. 25 drink both tea and coffee, 20 drink both coffee and juice, 15 drink both tea and juice, and 5 drink none of the three. How many students drink all three?
- A. 0
- B. 5
- C. 10
- D. 15
Show answer and solution
Answer: (B) 5
Students drinking at least one = 100 − 5 = 95.
By inclusion–exclusion: n(T ∪ C ∪ J) = ΣSingle − ΣPairs + All three
95 = (60 + 50 + 40) − (25 + 20 + 15) + x = 150 − 60 + x ⇒ x = 5.
Sanity check: only-tea = 60 − 25 − 15 + 5 = 25, only-coffee = 10, only-juice = 10, all regions non-negative ✓.
By inclusion–exclusion: n(T ∪ C ∪ J) = ΣSingle − ΣPairs + All three
95 = (60 + 50 + 40) − (25 + 20 + 15) + x = 150 − 60 + x ⇒ x = 5.
Sanity check: only-tea = 60 − 25 − 15 + 5 = 25, only-coffee = 10, only-juice = 10, all regions non-negative ✓.
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