Single correct option
In how many distinct ways can the letters of the word BANANA be arranged so that the two N's are not next to each other?
- A. 20
- B. 36
- C. 60
- D. 40
Show answer and solution
Answer: (D) 40
Total arrangements of BANANA (3 A's, 2 N's, 1 B) = 6!/(3! · 2!) = 60.
Arrangements with the two N's together: treat NN as one block → B, A, A, A, [NN] → 5!/3! = 20.
Required = 60 − 20 = 40.
Alternative (gap method): Arrange B, A, A, A in 4!/3! = 4 ways; this creates 5 gaps; choose 2 gaps for the identical N's: C(5, 2) = 10. Total = 4 × 10 = 40.
Arrangements with the two N's together: treat NN as one block → B, A, A, A, [NN] → 5!/3! = 20.
Required = 60 − 20 = 40.
Alternative (gap method): Arrange B, A, A, A in 4!/3! = 4 ways; this creates 5 gaps; choose 2 gaps for the identical N's: C(5, 2) = 10. Total = 4 × 10 = 40.
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