Single correct option
In how many ways can 5 boys and 3 girls be seated in a row such that no two girls sit together?
- A. 720
- B. 7200
- C. 12000
- D. 14400
Show answer and solution
Answer: (D) 14400
First seat the 5 boys in a row: 5! = 120 ways. This creates 6 gaps (including the two ends) in which the 3 girls can be placed so that no two girls are adjacent. Choose and arrange girls in 3 of these 6 gaps: 6×5×4 = 120 ways. Total arrangements = 120×120 = 14,400.
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