Numerical answer
The sides of a triangle are 13 cm, 14 cm and 15 cm. What is the radius (in cm) of the circle that passes through all three vertices of the triangle?
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Answer: 8.125
The required circle is the circumcircle, with radius R = abc/(4 × Area).
Area by Heron's formula: s = (13 + 14 + 15)/2 = 21.
Area = √(21 × 8 × 7 × 6) = √7056 = 84 cm².
R = (13 × 14 × 15)/(4 × 84) = 2730/336 = 65/8 = 8.125 cm.
Tip: The 13-14-15 triangle is two right triangles (5-12-13 and 9-12-15) joined along the altitude 12, which gives the area 84 instantly. (Its inradius is Area/s = 4 — a common confusion.)
Area by Heron's formula: s = (13 + 14 + 15)/2 = 21.
Area = √(21 × 8 × 7 × 6) = √7056 = 84 cm².
R = (13 × 14 × 15)/(4 × 84) = 2730/336 = 65/8 = 8.125 cm.
Tip: The 13-14-15 triangle is two right triangles (5-12-13 and 9-12-15) joined along the altitude 12, which gives the area 84 instantly. (Its inradius is Area/s = 4 — a common confusion.)
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