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JEE Advanced 2024 Paper 2 · Physics · Atoms, Nuclei and Dual Nature of Radiation · medium

Hydrogen-like Li^2+ ions de-excite from the n=3 level to the n=2 level and the emitted photons fall on a metal plate of work function 5.0 eV. The…

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Hydrogen-like Li2+\mathrm{Li^{2+}} ions de-excite from the n=3n=3 level to the n=2n=2 level and the emitted photons fall on a metal plate of work function 5.0 eV5.0\ \mathrm{eV}. The most energetic photoelectrons enter a region of uniform magnetic field 1.0 mT1.0\ \mathrm{mT} perpendicular to their velocity. The radius of their circular path is closest to (use ground-state energy of hydrogen 13.6 eV13.6\ \mathrm{eV}, me=9.11×10−31 kgm_e=9.11\times10^{-31}\ \mathrm{kg}, e=1.60×10−19 Ce=1.60\times10^{-19}\ \mathrm{C})
  1. A. 1.17 cm1.17\ \mathrm{cm}
  2. B. 1.39 cm1.39\ \mathrm{cm}
  3. C. 0.58 cm0.58\ \mathrm{cm}
  4. D. 2.34 cm2.34\ \mathrm{cm}
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Answer: (A) 1.17 cm1.17\ \mathrm{cm}

For a hydrogen-like ion En=−13.6 Z2/n2 eVE_n=-13.6\,Z^2/n^2\ \mathrm{eV} with Z=3Z=3. The photon energy is 13.6×9(14−19)=17.0 eV13.6\times9\left(\tfrac14-\tfrac19\right)=17.0\ \mathrm{eV}. The maximum kinetic energy of photoelectrons is K=17.0−5.0=12.0 eV=1.92×10−18 JK=17.0-5.0=12.0\ \mathrm{eV}=1.92\times10^{-18}\ \mathrm{J}. The momentum is p=2mK=2×9.11×10−31×1.92×10−18=1.87×10−24 kg m s−1p=\sqrt{2mK}=\sqrt{2\times9.11\times10^{-31}\times1.92\times10^{-18}}=1.87\times10^{-24}\ \mathrm{kg\,m\,s^{-1}}. In the magnetic field, r=peB=1.87×10−241.60×10−19×10−3=1.17×10−2 mr=\dfrac{p}{eB}=\dfrac{1.87\times10^{-24}}{1.60\times10^{-19}\times10^{-3}}=1.17\times10^{-2}\ \mathrm{m}. Option (B) uses the photon energy 17 eV17\ \mathrm{eV} as the kinetic energy (forgetting the work function), (C) is half the correct radius (as if BB were 2 mT2\ \mathrm{mT}), and (D) doubles the radius. The correct option is (A).
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